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gatoon
08 ¡ØÁÀҾѹ¸ì 2016, 18:07
¶éÒ a$\equiv$báÅéÇ $a^n\equiv b^n\pmod{m}$ ·Ø¡æ $n\in \mathbb{N}$à»ç¹¨Ó¹Ç¹àµçÁºÇ¡$\mathbf{Z}^+$
:please::please::please:
Pitchayut
19 ¡ØÁÀҾѹ¸ì 2016, 17:50
ÍØ»¹Ñ¤ÃѺ ËÃ×Íãªé $a^n-b^n=(a-b)(a^{n-1}+a^{n-2}b+a^{n-3}b^2+...+b^{n-1})$
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