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cardinopolynomial 21 àÁÉÒ¹ 2012 16:59

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¤èҢͧ $\frac{(1+19)(1+\frac{19}{2})(1+\frac{19}{3})....(1+\frac{19}{91})}
{(1+91)(1+\frac{91}{2})(1+\frac{91}{3}).....(1+\frac{91}{19})}$ à»ç¹à·èÒäÃ

Night Baron 21 àÁÉÒ¹ 2012 17:32

:great::great:ÊǨÃÔ§æ¤ÃѺ µÑ´¡Ñ¹ä´é 1¾Í´ÕàŤÃѺ

HL~arc-en-ciel 21 àÁÉÒ¹ 2012 17:57

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»Ò¡¡Òà«Õ¹ 22 àÁÉÒ¹ 2012 21:38

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polsk133 23 àÁÉÒ¹ 2012 00:05

ËÅèÍä´éäËÁ¤ÃѺ 555+

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poper 23 àÁÉÒ¹ 2012 00:37

ÊǧÒÁ¤ÃѺ ªÍºæææ:great:

TheSugardrop23 25 àÁÉÒ¹ 2012 20:07

·ÓÂѧä§ËÃͤèÐ ªèÇÂÊ͹ÇÔ¸Õ˹èÍÂä´éäËÁ¤Ð

a-Little-Man 25 àÁÉÒ¹ 2012 20:27

ÍéÒ§ÍÔ§:

¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ TheSugardrop23 (¢éͤÇÒÁ·Õè 139198)
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Åͧ¤Ù³´éÇ $\frac{91!}{91!}$ ´Ù¹Ð¤ÃѺ :happy:

TheMintoRB 25 àÁÉÒ¹ 2012 21:09

à¾Ô觷Óä´é¢éÍáá ¨Ò¡·Õè·Óã¹àÇ纹ÕéÁÒ ÍШÖëÂ

poper 26 àÁÉÒ¹ 2012 01:40

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$$\frac{(20)(\frac{21}{2})(\frac{22}{3})...(\frac{38}{19})(\frac{39}{20})...(\frac{110}{91})}{(92)(\frac{93}{2})(\frac{94}{3}).. .(\frac{110}{19})}$$ $$=\frac{20\cdot21\cdot22\cdot...\cdot110}{2\cdot3\cdot...\cdot91}\times\frac{2\cdot3...\cdot19}{92\cdot93\cdot...\cdot110}$$ $$=\frac{20\cdot21\cdot...\cdot91}{20\cdot21\cdot...\cdot91}=1$$


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