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$g(x)=2x-1$
$f(x)=\frac{2x-1}{x+1}$ $f'(1)=\frac{3}{4}$ |
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¨Ò¡ $\int g(x)dx=x^2-x+c$
´Ô¿·Ñé§Êͧ¢éÒ§¨Ðä´é $g(x)=2x-1$ áÅÐ $g(x)=(x+1)f(x)$ ´Ñ§¹Ñé¹ $(x+1)f(x)=2x-1$ ¨Ðä´éÇèÒ $f(x)=\frac{2x-1}{x+1}$ $f'(x)=\frac{3}{(x+1)^2}$ ãªéÊٵôԿ¼ÅËÒà $f'(1)=\frac{3}{4}$ ¤ÃѺ¼Á |
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àÇÅÒ·ÕèáÊ´§·Ñé§ËÁ´ à»ç¹àÇÅÒ·Õè»ÃÐà·Èä·Â (GMT +7) ¢³Ð¹Õéà»ç¹àÇÅÒ 19:55 |
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