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2)


$72^x + 72 < 2^{3x+3} + 3^{2x+2}$

$2^{3x} 3^{2x} - 3^{2x+2} - 2^{3x+3} + 2^3 3^2 < 0$

$\frac{2^{3x} 3^{2x}}{72} - \frac{3^{2x}}{8} - \frac{2^{3x}}{9} + 1 < 0$

$(\frac{3^{2x}}{8} - 1) (\frac{2^{3x}}{9} - 1) < 0$