1)
ให้รถไฟความเร็ว $v_1, v_2$ $m/s$
$\frac{270+170}{v_1+v_2} = 12$
$\frac{440}{12} = v_1+v_2$ --- (1)
$\frac{270+170}{v_1-v_2} = 60$
$\frac{88}{12} = v_1-v_2$ --- (2)
(1) + (2)
$\frac{528}{12} = 2 v_1$
$22 = v_1$
$V_1 = 22\times 3.6 = 79.2$ $km/h$
$\frac{44}{3} = v_2$
$V_2 = \frac{44}{3}\times 3.6 = 52.8$ $km/h$
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