4 ตอนที่ 2
$\frac{3}{x}log2=\frac{3}{y} log3=\frac{2}{z}(log2+log3)$
$y=x\frac{log3}{log2}$
$z=\frac{2x(log2+log3)}{log2} $
$\frac{x+y}{z}$
$=\frac{x+x\frac{log3}{log2}}{\frac{2x(log2+log3)}{log2} } $
$=\frac{1+\frac{log3}{log2}}{\frac{2(log2+log3)}{log2} } $
$=\frac{log2+log3}{2(log2+log3)}=0.5$
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