11.area of ABCDEFGHIJKL =$ (6 * \triangle ALP) * (area of PQRSTU)$
area of ABCDEFGHIJKL = $(6* \frac{\sqrt{3}}{4} *4^{2}) + (\frac{3\sqrt{3}}{2}*2^{2})$
area of ABCDEFGHIJKL = $24\sqrt{3} + 6\sqrt{3} = 30\sqrt{3} $
area of PQRSTU = $6\sqrt{3} $
$\therefore \frac{ABCDEFGHIJKL}{PQRSTU} = \frac{30\sqrt{3}}{6\sqrt{3}} = 5 $
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