Credit
http://sites.google.com/site/pemooff...st/prtst-april
Official Problem for $a,b,c\geq 0$ prove that
$\sum_{cyc} a\sqrt{6a+21b}\leq \sqrt{8\sum_{cyc} a^3+30\sum_{cyc} a^2b+15\sum_{cyc} ab^2+84abc}$
โจทย์จริงค่อนข้างยาก เลยทำให้ง่ายลงหน่อย
My easier version for everyone!!
for $a,b,c\geq 0$ prove that
$\sum_{cyc} a\sqrt{6a+21b}\leq \sqrt{10\sum_{cyc} a^3+33\sum_{cyc} a^2b+16\sum_{cyc} ab^2+66abc}$
