Domain & Range T_T
I have just studied relations : Domain and Range Mr. Metree Sritongtae
Find Domain and Range
1. $r= \left\{\,\right. (x,y) \in R \times R \left|\,\right. y= \frac{1}{\sqrt{4-9x^2} } \left.\,\right\} $
2. $r=\left\{\,\right. (x,y) \in R \times R \left|\,\right. \left|\,\right. x\left|\,\right. + \left|\,\right. y\left|\,\right. = 1 \left.\,\right\} $
3.$ r = \left\{\,\right. (x,y) \in R \times R \left|\,\right. y = \frac{1}{x^2-2x-3} \left.\,\right\} $
4.$ r = \left\{\,\right. (x,y) \in R \times R \left|\,\right. y= \frac{3}{4-\left|\,\right. x\left|\,\right. } \left.\,\right\} $
5. $ r = \left\{\,\right. (x,y) \in R \times R \left|\,\right. y=\sqrt{x^2+16}\left.\,\right\} $
6. $ r = \left\{\,\right. (x,y) \in R \times R \left|\,\right. \sqrt{x+1}+\sqrt{y-1} = 3 \left.\,\right\} $
7. $ r = \left\{\,\right. (x,y) \in R \times R \left|\,\right. y=\frac{-4}{\sqrt{9-\left|\,\right. x\left|\,\right. } }\left.\,\right\} $
8.$ r = \left\{\,\right. (x,y) \in R \times R \left|\,\right. y=\frac{3x\left|\,\right. x\left|\,\right. }{x^2}\left.\,\right\}$
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25 มีนาคม 2010 22:39 : ข้อความนี้ถูกแก้ไขแล้ว 3 ครั้ง, ครั้งล่าสุดโดยคุณ Siren-Of-Step
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