$$\frac{3^{1-n}}{2^{-n-1}}\times\frac{5^{-2n+2}}{3^{-2n}}\times\frac{5^{3n-3}}{(2\cdot3\cdot5)^{n-1}}$$
$=\frac{(3^{1-n})(5^{n-1})}{(2^{-2})(3^{-n-1})(5^{n-1})}$
$=3^2\cdot2^2=36$
$$\frac{3^{2n+1}}{3^{-2n}}\times\frac{3^{4n^2-1}}{3^{4n^2+4n}}$$
$=\frac{3^{4n^2+2n}}{3^{4n^2+2n}}=1$
ดังนั้น $36-1=35$