solution
$\frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} + \frac{1}{42} + ...... + \frac{1}{420}$
= 1 - $\frac{1}{2} + \frac{3}{6} - \frac{2}{6} + \frac{4}{12} - \frac{3}{12} + \frac{5}{20} - \frac{4}{20} + \frac{6}{30} - \frac{5}{30} + \frac{7}{42} - \frac{6}{42} + .... + \frac{21}{420} - \frac{20}{420}$
= 1 - $\frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3} - \frac{1}{4} + \frac{1}{4} - \frac{1}{5} + \frac{1}{5} - \frac{1}{6} + \frac{1}{6} - \frac{1}{7} + .... + \frac{1}{20} - \frac{1}{21}$
= 1 - $\frac{1}{21} = \frac{20}{21}$
เพิ่งรู้ว่าเคยมีอยู่MCTเลยยืมแนวคิดคุณอู๋มา
(จะได้ประหยัดเวลา)
