[อัจฉริยะข้ามจักรวาล]

from 36. x+y=280,xy=19551
let x and y is root of
t^2-(x+y)t+xy=0 Substituting x,y
Therefore
t^2-280t+19551=0
...
t=140\pm\sqrt{49}
t=140\pm 7
t=147,133
Thus to number is different 147-133=14

ANS 14