ข้อ 2 น่ะครับ
ถ้า $\left( {\sqrt {\frac{8}{{125}}} } \right)^4 = \left( {\frac{{16}}{{625}}} \right)^{\frac{1}{x}} $ จงหาค่า $x$
วิธีทำ
$\begin{array}{l}
\left( {\sqrt {\frac{8}{{125}}} } \right)^4 = \left( {\frac{{16}}{{625}}} \right)^{\frac{1}{x}} \\
\left[ {\left( {\frac{8}{{125}}} \right)^{\frac{1}{2}} } \right]^4 = \left( {\frac{{16}}{{625}}} \right)^{\frac{1}{x}} \\
\left[ {\left( {\frac{{2^3 }}{{5^3 }}} \right)^{\frac{1}{2} \times 2} } \right]^2 = \left( {\frac{{2^4 }}{{5^4 }}} \right)^{\frac{1}{x}} \\
\left( {\frac{{2^3 }}{{5^3 }}} \right)^2 = \left( {\frac{{2^4 }}{{5^4 }}} \right)^{\frac{1}{x}} \\
\left[ {\left( {\frac{2}{5}} \right)^3 } \right]^2 = \left[ {\left( {\frac{2}{5}} \right)^4 } \right]^{\frac{1}{x}} \\
\left( {\frac{2}{5}} \right)^6 = \left( {\frac{2}{5}} \right)^{\frac{4}{x}}
\end{array}$
$\therefore 6= \frac{4}{x}$ จะได้ว่า $x= \frac{2}{3}$
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