[RER]

$\frac{a+b+c}{a+b}+\frac{a+b+c}{c+b}+\frac{a+b+c}{a+c}=\frac{143}{17}$

$\frac{c}{b+a}+1+\frac{b}{c+a}+1+\frac{a}{b+c}+1=\frac{143}{17}$

$\frac{c}{b+a}+\frac{b}{c+a}+\frac{a}{b+c}=\frac{92}{17}$