$9N=5(10^{12}-1)$
$=5(10^6-1)(10^6+1)$
$=5(10^3-1)(10^3+1)(10^2+1)(10^4-10^2+1)$
$=5(10-1)(10^2+10+1)(10+1)(10^2-10+1)(10^2+1)(10^4-10^2+1)$
$=5(9)(3)(37)(11)(7)(13)(101)(9901)$
$N=3\times 5\times 7\times 11\times 13\times 37\times 101\times 9901$
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