[Mol3ilE]

ข้อความเดิมเขียนโดยคุณ Euler-Fermat

$ (2x^2 + 4x -3)^3 = 8x^6+48x^5+60x^4+80x^3-90x^2-108x-27 =(2x^2+Ax-3)^3 $
$\therefore A = 4$

http://www.wolframalpha.com/input/?i...%2B4x-3%29%5E3