7.ปรับเป็นเศษส่วนพหุนามจะได้
$1 + \frac{2}{(-1 + x)} + x -(2 + \frac{3}{(-2 + x)} + x)=-3 + x + \frac{2}{(3 + x)}-(-2 + x + \frac{1}{(2 + x)})$
$=\frac{2}{(-1 + x)}-\frac{3}{(-2 + x)}-1=-1+\frac{2}{(3 + x)}-\frac{1}{(2 + x)}$
แก้สมการจะได้ $x=-1$
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