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Old 14 ¾ÄȨԡÒ¹ 2009, 16:10
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15 ¾ÄȨԡÒ¹ 2009 21:32 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ RT,,Ant~*
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  #2  
Old 14 ¾ÄȨԡÒ¹ 2009, 16:47
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1.¡Ó˹´àÅ¢ 1 , 3 , 6 , 10 , ... , n

ãËéàÅ¢¹Õéá·¹¨Ó¹Ç¹ÊÒÁàËÅÕèÂÁ·Õèà»ç¹ä»ä´é ¨§ËҨӹǹÊÒÁàËÅÕèÂÁ·ÕèÁÒ¡·ÕèÊØ´·Õè¹éÍ¡ÇèÒ 2009

2.â¹ÅÙ¡àµëÒ 4 ÅÙ¡ 1 ¤ÃÑé§ ¨§ËÒ¤ÇÒÁ¹èÒ¨Ðà»ç¹·Õè¨Ðä´é¼Å¤Ù³¢Í§áµéÁà·èҡѺ 36

3. ãËéNà»ç¹¨Ó¹Ç¹¹Ó⪤à»ç¹¨Ó¹Ç¹àµçÁµÃÑé§áµè1000-9999ÁÕËÅѡ˹èÇÂáÅÐËÅÑ¡¾Ñ¹¤×Í1 ¼ÅÃÇÁ¢Í§¨Ó¹Ç¹¹Ó⪤·Ø¡¨Ó¹Ç¹à·èҡѺà·èÒã´

$a^2 +b^2+c^2 +2a -4b +6c +14 \leqslant 0 $

¨§ËÒ b-2ac

_____________________________________

$ãËé x à»ç¹¨Ó¹Ç¹à©¾ÒÐ áÅÐ y à»ç¹¨Ó¹Ç¹àµçÁºÇ¡ ·ÕèÊÍ´¤Åéͧ¡Ñº 99x+1 = y^2
¨§ËҼźǡ¢Í§¤èÒ y ·Õèà»ç¹ä»ä´é $

1. 98
2. 99
3. 198
4. 199

Â×¹ÍÂÙ躹ËͤÍÂáËè§Ë¹Öè§ ÁͧàËç¹ÂÍ´àÊÒ¸§à»ç¹ÁØÁ¡éÁ (¢Í͹حҵÔãªé a) a áÅÐàËç¹°Ò¹àÊÒ¸§à»ç¹ÁØÁ B

ãËé ËͤÍ¡ѺàÊÒ¸§ËèÒ§¡Ñ¹ y Á. (¼ÁÇèÒà¤éÒãËéËÒ¤ÇÒÁÊÙ§¢Í§Ëͤ͹éÐ)

¨§ËÒ¤ÇÒÁÊÙ§¢Í§ËͤÍÂ

$ãËé ¤ÇÒÁÊÙ§¢Í§ ËͤÍ = h$

$ä´éÇèÒ \frac{sinA}{cosA} = \frac{h}{y}$

$ y(\frac{sinA}{cosA}) = h ---(1)$

áÅÐ $\frac{sinB}{cosB} = \frac{h}{y}$


$ y(\frac{sinB}{cosB}) = h ----(2)$

(1)=(2)

$y(\frac{sinA}{cosA}) = y(\frac{sinB}{cosB}) $
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1.2 à¾ÃÒÐ àÁ¦ÊÕá´§ ÊÕÊéÁ ËÃ×Í ÊÕªÁ¾Ù ¹Ñé¹â´Â»¡µÔà¡Ô´ã¹ªèǧ ¾ÃÐÍÒ·ÔµÂì¢Öé¹ áÅÐ ¾ÃÐÍÒ·ÔµÂ쵡 à¡Ô´¨Ò¡¡ÒáÃÐà¨Ô§¢Í§áʧ㹪Ñ鹺ÃÃÂÒ¡ÒÈ (Credit : Wikipedia)

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4.2(áµè¼ÁµÍº4) http://www.hilalthailand.com/oursky/...x.php?cat_id=1

5.3 à¾ÃÒÐ ä·ÂÍÂÙè«Õ¡âÅ¡à˹×Í àÁ×èÍâÅ¡Ëѹ«Õ¡ãµéà¢éÒä·Â¨Ö§à»ç¹Ä´Ù˹ÒÇ

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ÍÒÂØ 35 - 55 ¶Ù¡µÑ´Ãѧä¢è¢éÒ§¹Ö§ Ãͺà´×͹¨ÐËÒ¤ÃÖè§Ë¹Öè§ à¾ÃÒÐÃѧä¢è¨Ð¼ÅÑ´µ¡ä¢è¢éÒ§ÅÐà´×͹
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7.3 à¾ÃÒÐ àÃÔèÁ¼ÊÁÊÒÃàÁÅÒÁÕ¹ «Öè§à»ç¹ÊÒÃà¤ÁÕµéͧËéÒÁŧä»ã¹¹ÁàÁ×èÍ»ÅÒ»շÕèáÅéÇ à¾×èÍà¾ÔèÁ»ÃÔÁÒ³â»ÃµÕ¹ãËéä´éµÒÁ·ÕèÁҵðҹ¡Ó˹´ (http://www.tlcthai.com/webboard/view...&post_id=40943)

8.4(äÁèá¹èã¨)

9.3 (http://variety.mcot.net/vdo738)

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15 ¾ÄȨԡÒ¹ 2009 21:41 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 2 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ RT,,Ant~*
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  #3  
Old 14 ¾ÄȨԡÒ¹ 2009, 16:48
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ÊͺÁËÔ´Å ÁÕ⨷ÂìàÊÕ´éǹФÃѺ .

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Old 14 ¾ÄȨԡÒ¹ 2009, 16:49
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ÊͺÁËÔ´Å ÁÕ⨷ÂìàÊÕ´éǹФÃѺ .

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14 ¾ÄȨԡÒ¹ 2009 17:07 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ ¤uÃÑ¡la¢
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Old 14 ¾ÄȨԡÒ¹ 2009, 17:25
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¢Í¤ÇÒÁ¡ÃسÒÁÒâ¾Êµì·ÕèÅÔ§¤ì´éÒ¹ÅéÒ§ ¨Ðä´éäÁ軹¡Ñ¹ ¤ÃѺ ¢Íº¤Ø³¤ÃѺ
http://www.mathcenter.net/forum/show...9059#post69059
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  #6  
Old 14 ¾ÄȨԡÒ¹ 2009, 17:43
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¢éÍ·Õè¡ÓÅѧ¨Ðâ¾Êµì¡çâ¾Êä» ËÁ´áÅéÇÅèФÃѺ 5+

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  #7  
Old 14 ¾ÄȨԡÒ¹ 2009, 17:45
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ÍèÍ ÁÕ¢é͹֧ à»ç¹¢éÍÊͺ ྪÃÂÍ´Á§¡Ø¯ 50 ´éǹéÐ

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Old 14 ¾ÄȨԡÒ¹ 2009, 17:51
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Mwit53
¢éÍ24) ãËéNà»ç¹¨Ó¹Ç¹¹Ó⪤à»ç¹¨Ó¹Ç¹àµçÁµÃÑé§áµè1000-9999ÁÕËÅѡ˹èÇÂáÅÐËÅÑ¡¾Ñ¹¤×Í1 ¼ÅÃÇÁ¢Í§¨Ó¹Ç¹¹Ó⪤·Ø¡¨Ó¹Ç¹à·èҡѺà·èÒã´
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  #9  
Old 14 ¾ÄȨԡÒ¹ 2009, 17:51
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$a^2 +b^2+c^2 +2a -4b +6c +14 \leqslant 0 $

¨§ËÒ b-2ac

_____________________________________

$ãËé x à»ç¹¨Ó¹Ç¹à©¾ÒÐ áÅÐ y à»ç¹¨Ó¹Ç¹àµçÁºÇ¡ ·ÕèÊÍ´¤Åéͧ¡Ñº 99x+1 = y^2
¨§ËҼźǡ¢Í§¤èÒ y ·Õèà»ç¹ä»ä´é $

1. 98
2. 99
3. 198
4. 199

ÊèǹµÑǼÁä´é 98 + 100 = 198 : )

14 ¾ÄȨԡÒ¹ 2009 17:51 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ RT,,Ant~*
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  #10  
Old 14 ¾ÄȨԡÒ¹ 2009, 17:56
banker banker äÁèÍÂÙèã¹Ãкº
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¢éÍÊÒÁàËÅÕèÂÁÁØÁ©Ò¡µÍº AC = 185

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  #11  
Old 14 ¾ÄȨԡÒ¹ 2009, 17:57
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ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ RT,,Ant~* View Post
$a^2 +b^2+c^2 +2a -4b +6c +14 \leqslant 0 $

¨§ËÒ b-2ac

$ ¨Ñ´ÃÙ» (a^2+2a+1) + (b^2-4b+4) + (c^2+6c+9) \leqslant 0 $

$ (a+1)^2 + (b-2)^2 + (c+3)^2 \leqslant 0 $

$ ¨Ðä´é a = -1 b = 2 c = -3

á·¹¤èÒ

$ 2 - (2)(-1)(-3) = -4
_____________________________________

$ãËé x à»ç¹¨Ó¹Ç¹à©¾ÒÐ áÅÐ y à»ç¹¨Ó¹Ç¹àµçÁºÇ¡ ·ÕèÊÍ´¤Åéͧ¡Ñº 99x+1 = y^2
¨§ËҼźǡ¢Í§¤èÒ y ·Õèà»ç¹ä»ä´é $

1. 98
2. 99
3. 198
4. 199

ÊèǹµÑǼÁä´é 98 + 100 = 198 : )
$99x = y^2 - 1$

$99x = (y-1)(y+1)$

$x = 97 y = 98 $

$x = 101 y = 100 $

____________________

14 ¾ÄȨԡÒ¹ 2009 17:58 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ RT,,Ant~*
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  #12  
Old 14 ¾ÄȨԡÒ¹ 2009, 18:06
banker banker äÁèÍÂÙèã¹Ãкº
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ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ RT,,Ant~* View Post
$


$ãËé x à»ç¹¨Ó¹Ç¹à©¾ÒÐ áÅÐ y à»ç¹¨Ó¹Ç¹àµçÁºÇ¡ ·ÕèÊÍ´¤Åéͧ¡Ñº 99x+1 = y^2
¨§ËҼźǡ¢Í§¤èÒ y ·Õèà»ç¹ä»ä´é $

1. 98
2. 99
3. 198
4. 199

ÊèǹµÑǼÁä´é 98 + 100 = 198 : )

$99x+1 = y^2$

$y^2 - 1 = 99X$

$(y-1)(y+1) = (100-1)(100+1) -----> y = 100 $


$(y+1)(y-1) = (98+1)(98 - 1) -----> y = 98 $


¼ÅºÇ¡¨Ö§à»ç¹ 100+98 = 198
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  #13  
Old 14 ¾ÄȨԡÒ¹ 2009, 18:08
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ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ banker View Post
$99x+1 = y^2$

$y^2 - 1 = 99X$

$(y-1)(y+1) = (100-1)(100+1) -----> y = 100 $


$(y+1)(y-1) = (98+1)(98 - 1) -----> y = 98 $


¼ÅºÇ¡¨Ö§à»ç¹ 100+98 = 198

à¾ÃÒР⨷Âì¡Ó˹´ x à»ç¹¨Ó¹Ç¹à©¾ÒÐ àŵéͧ ä´é x = 97 ¡Ñº 101 ÍèФÃѺ

áµèªéÍÂÊì¡çÊÇÂàÍÒ¡Òà æ

ʹءÁÒ¡¤ÃѺ . ( áµèÇÔ·ÂìäÁè¤èÍÂàÍÒàÃ×èͧà·èÒäËÃè.. äÁèÁÑè¹ã¨ æ )
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #14  
Old 14 ¾ÄȨԡÒ¹ 2009, 18:21
RT,,Ant~*'s Avatar
RT,,Ant~* RT,,Ant~* äÁèÍÂÙèã¹Ãкº
ÅÁ»ÃÒ³¤ØéÁ¤ÃͧÃèÒ§
 
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RT,,Ant~* is on a distinguished road
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Â×¹ÍÂÙ躹ËͤÍÂáËè§Ë¹Öè§ ÁͧàËç¹ÂÍ´àÊÒ¸§à»ç¹ÁØÁ¡éÁ (¢Í͹حҵÔãªé a) a áÅÐàËç¹°Ò¹àÊÒ¸§à»ç¹ÁØÁ B

ãËé ËͤÍ¡ѺàÊÒ¸§ËèÒ§¡Ñ¹ y Á. (¼ÁÇèÒà¤éÒãËéËÒ¤ÇÒÁÊÙ§¢Í§Ëͤ͹éÐ)

¨§ËÒ¤ÇÒÁÊÙ§¢Í§ËͤÍÂ

$ãËé ¤ÇÒÁÊÙ§¢Í§ ËͤÍ = h$

$ä´éÇèÒ \frac{sinA}{cosA} = \frac{h}{y}$

$ y(\frac{sinA}{cosA}) = h ---(1)$

áÅÐ $\frac{sinB}{cosB} = \frac{h}{y}$


$ y(\frac{sinB}{cosB}) = h ----(2)$

(1)=(2)

$y(\frac{sinA}{cosA}) = y(\frac{sinB}{cosB}) $

ÂéÒ y ÁÒź áÅéÇ ¨Ñ´ÃÙ» ¡ç¨Ðä´é¤èҢͧ h ÍèФÃѺ * (¼Á¾ÔÁ¾ìäÁè¤èͨÐà¡è§à·èÒäËÃè æ ú¡Ç¹·ÓµèÍ´éǹФÃѺ)
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24 ¾ÄȨԡÒ¹ 2009 11:23 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 3 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ RT,,Ant~*
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #15  
Old 14 ¾ÄȨԡÒ¹ 2009, 18:26
¤uÃÑ¡la¢'s Avatar
¤uÃÑ¡la¢ ¤uÃÑ¡la¢ äÁèÍÂÙèã¹Ãкº
ÅÁ»ÃÒ³¤ØéÁ¤ÃͧÃèÒ§
 
Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 11 Á¡ÃÒ¤Á 2009
¢éͤÇÒÁ: 277
¤uÃÑ¡la¢ is on a distinguished road
Default

àÍÒ 2 ¢éÍ
äÁèÃÙéÇèÒ¶Ù¡ÃÖà»ÅèҹФÃѺ
µÍº 2+3+5+7+11+13+17+19+23+29 = 129
µÍº 32 Ẻ
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14 ¾ÄȨԡÒ¹ 2009 18:28 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ ¤uÃÑ¡la¢
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