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Old 27 àÁÉÒ¹ 2014, 09:07
i^i i^i äÁèÍÂÙèã¹Ãкº
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ÍÂÒ¡·ÃÒºÇèÒ µÃ§ [2^(x-1)]^2 = 2^2x-2 = 4^x-1 µÒÁÊÁºÑµÔàŢ¡¡ÓÅѧ¢éÍä˹¤ÃѺ
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Old 28 àÁÉÒ¹ 2014, 01:46
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$(a^m)^n=a^{mn}=(a^n)^m$ ¤ÃѺ
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