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ÊÁѤÃÊÁÒªÔ¡ | ¤ÙèÁ×Í¡ÒÃãªé | ÃÒª×èÍÊÁÒªÔ¡ | »¯Ô·Ô¹ | ¢éͤÇÒÁÇѹ¹Õé | ¤é¹ËÒ |
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à¤Ã×èͧÁ×ͧ͢ËÑÇ¢éÍ | ¤é¹ËÒã¹ËÑÇ¢é͹Õé |
#1
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ªèÇÂ˹èͤÃѺ ¢ÍäÁè¶Ö¡
¡Ó˹´¾ËعÒÁ $$P(x)=x^6+ax^5+bx^4+cx^3+dx^2+ex+f$$ àÁ×èÍ $a,b,c,d,e,f$ à»ç¹¤èÒ¤§·Õè ¶éÒ $P(1) = 15 , P(2) = 22 , P(3) = 29 , P(4) = 36 , P(5) = 43 , P(5) = 43 , P(6) = 50$ $$P(7) = ??$$
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Fortune Lady
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#2
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á¤è¤Ô´àÅ¢¡ç¶Ö¡áÅéǤÃѺ áÅéǨÐãËéäÁè¶Ö¡ä´éä§
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#3
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ÁÕÇÔ¸ÕÍ×蹹͡¨Ò¡
$1+a+b+c+d+e+f = 15$ $a+b+c+d+e+f = 14$ . . . áµèàÅ¢ÂÔè§àÂÍСçÂÔ觶֡ ¢ÍÇÔ¸ÕẺäÁèãªèẺ¹Õé Ẻ¶Ö¡¡çä´é¤ÃѺ áµèÅ´¤ÇÒÁ¶Ö¡¨Ò¡ÇÔ¸Õ¹Õé˹èͤÃѺ
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Fortune Lady
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#4
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á¹Ç¢éÍÊͺ ʾ°. Ãͺ 2 ÍФÃѺ
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Fortune Lady
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#5
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ÅͧãËé $Q(x)=P(x)-(8+7x)$
¨Ðä´é $Q(1)=Q(2)=...=Q(6)=0$ ·ÕèàËÅ×Í¡çäÁèÁÕäÃáÅéÇ
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à˹×Í¿éÒÂѧÁÕ¿éÒáµèà˹×Í¢éÒµéͧäÁèÁÕã¤Ã »Õ¡¢Õé¼×駢ͧ»ÅÍÁ§Ñé¹ÊԹР...âÅ¡¹ÕéâË´ÃéÒ¨ÃÔ§æ ÁѹãËé¤ÇÒÁÊØ¢¡ÑºàÃÒ áÅéÇÊØ´·éÒ Áѹ¡çàÍҤ׹ä»... |
#6
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¹éͧ siren-of-step ¹Ñè§à½éÒºÍÃì´ËÃͤÃѺ àËç¹µÑ駡ÃзÙéàÂÍÐàÅ ´ÕÁÒ¡ ¿Ôµæ ¾Õè¨ÐªèǵͺãËé੾ÒзÕèªèÇÂä´éÅСѹ ªèǧ¹Õé»Ô´à·ÍÁÁÕàÇÅÒàÂÍÐÍÂÙè
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#7
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777 à»ç¹¤ÓµÍºÊØ´·éÒ¤ÃѺ
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#8
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¼ÁäÁèä´é¹Ñè§à½éÒËÃÍ¡¤ÃѺ ¡ÇèҨСÅѺÁÒ ¡ç ºèÒ ¡ÇèÒ æ ÍФÃѺ
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Fortune Lady
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#9
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ÁÕ⨷Âì·Õè·ÓäÁèä´éÍÕ¡áÅéÇ
¡Ó˹´ãËé $a,b,c \in I^+$ «Öè§ÊÍ´¤Åéͧ¡ÑºÊÁ¡Òà $$a^2(b+c)^2 = (3a^2 + a+ 1)b^2c^2$$ $$b^2(c+a)^2 = (4b^2 + b + 1)c^2a^2$$ $$c^2(a+b)^2 = (5c^2 + c + 1)a^2b^2$$ áÅéÇ $13a+14b+15c$ ÁÕ¤èÒà·èÒã´ ÍÕ¡¢é͹ФÃѺ àËç¹ÇèÒÁÕ¤¹à¤Â·ÓÁÒáÅéÇ ËÒ¡ÃзÙéäÁèà¨Í $$\frac{1}{x} +\frac{1}{y} =\frac{1}{2008}$$ ÁÕ¡Õè¤ÓµÍº
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Fortune Lady
22 ÁÕ¹Ò¤Á 2010 16:46 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 3 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ Siren-Of-Step |
#10
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Hint : Sange & Yasha
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àÇÅÒ·ÕèàËÅ×ÍÍÂÙèÁÕÇÔ¸Õ¡ÒÃãªéÊͧẺ ¤×Í ·Ò§·ÕèàÃÕº§èÒÂäÁèÁÕÍÐäà ¡ÑºÍÕ¡·Ò§ ·Õè·Ø¡ÍÂèÒ§ÅéǹÁËÑȨÃÃÂì |
#11
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$c^2(a+b)^2 = (5c^2 + a + 1)a^2b^2$
¹èÒ¨Ðà»ç¹ $c^2(a+b)^2 = (5c^2 +$ $c$ $+ 1)a^2b^2$ ËÃ×Íà»ÅèÒ¤ÃѺ à¾ÃÒÐà·Õº¡ÑºÊͧÊÁ¡ÒÃáááÅéǾ¨¹ì¹Õé¹èÒ¨Ðà»ç¹$c$ÁÒ¡¡ÇèÒ$a$
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"¶éÒàÃÒÅéÁºèÍÂæ ã¹·ÕèÊØ´àÃÒ¨ÐÃÙéÇèÒ¶éÒ¨ÐÅéÁ ÅéÁ·èÒä˹¨Ðà¨çº¹éÍ·ÕèÊØ´ áÅÐÃÙéÍÕ¡ÇèÒµèÍä»·ÓÂѧ䧨ÐäÁèãËéÅéÁÍÕ¡ ´Ñ§¹Ñ鹨§ÍÂèÒ¡ÅÑÇ·Õè¨ÐÅéÁ"...ÍÒ¨ÒÃÂìÍӹǠ¢¹Ñ¹ä·Â ¤ÃÑé§áá㹪ÕÇÔµ·ÕèÊͺ¤³ÔµÊÁÒ¤Á¤³ÔµÈÒʵÃìàÁ×èÍ»Õ2533...¼Áä´éá¤è24¤Ðá¹¹(¨Ò¡ÃéͤÐá¹¹) |
#12
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ÍéÒ§ÍÔ§:
$xy = 2008x+2008y$ $xy-2008x-2008y=0$ $xy-2008x-2008y+2008^2 = 2008^2 = (2^3\times 251)^2$ $(x-2008)(y-2008) = 2^6\times 251^2$ ¨Ö§ÁÖ$ \ (6+1)(2+1) = 21 \ $ ¤ÓµÍº
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ÁÒËÒ¤ÇÒÁÃÙéäÇéµÔÇËÅÒ¹ áµèËÅÒ¹äÁèàÍÒàÅ¢áÅéÇ à¢éÒÁÒ·ÓàÅ¢àÍÒÁѹÍÂèÒ§à´ÕÂÇ ¤ÇÒÁÃÙéà»ç¹ÊÔè§à´ÕÂÇ·ÕèÂÔè§ãËé ÂÔè§ÁÕÁÒ¡ ÃÙéÍÐäÃäÁèÊÙé ÃÙé¨Ñ¡¾Í (¡àÇ鹤ÇÒÁÃÙé äÁèµéͧ¾Í¡çä´é ËÒäÇéÁÒ¡æáËÅдÕ) (áµè¡çÍÂèÒãËéÁÒ¡¨¹·èÇÁËÑÇ àÍÒµÑÇäÁèÃÍ´) |
#13
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ÍéÒ§ÍÔ§:
¾Ô¨ÒÃ³Ò $$a^2(b+c)^2-(3a^2+a+1)b^2c^2 = 0$$ $a^2b^2c^2$ ËÒõÅÍ´ (Sange #1)$$\frac{b^2+2bc+c^2}{b^2c^2}-\frac{3a^2-a-1}{a^2}=0$$ $$\frac{1}{c^2}+\frac{2}{bc}+\frac{1}{b^2} - 3 - \frac{1}{a} - \frac{1}{a^2}=0$$ $$(\frac{1}{c}+\frac{1}{b})^2-\frac{1}{a}-\frac{1}{a^2}-3$$ ä´éÃٻẺ(Sange #2 , #3)ÁѹÁÒ¹ÓÁҺǡ(Yasha) ÊÁÁµÔµÑÇá»Ã ¨º ã¤ÃÁÕÇÔ¸Õ§èÒ¡ÇèÒ¼ÁäËÁ¤ÃѺ
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Fortune Lady
22 ÁÕ¹Ò¤Á 2010 16:58 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 2 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ Siren-Of-Step |
#14
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·ÓẺ¹ÕéËÃ×Íà»ÅèÒ¤ÃѺ
¼Áá»Å§áºº¹Õé $a^2(b+c)^2 = (3a^2 + a+ 1)b^2c^2$ $\frac{a^2(b+c)^2}{b^2c^2} = (3a^2 + a+ 1)$ $(\frac{a(b+c)}{bc})^2 =a^2(\frac{1}{b} +\frac{1}{c})^2= (3a^2 + a+ 1)$ $(\frac{1}{b} +\frac{1}{c})^2= (3+\frac{1}{a} +\frac{1}{a^2} )$ $\frac{1}{b^2} +\frac{1}{c^2}-\frac{1}{a^2} = (3+\frac{1}{a} -\frac{2}{bc} )$....(1) ÍÕ¡ÊͧÊÁ¡Ò÷ÓàËÁ×͹¡Ñ¹¨Ðä´é $\frac{1}{a^2} +\frac{1}{c^2}-\frac{1}{b^2} = (4+\frac{1}{b} -\frac{2}{ac} )$....(2) $\frac{1}{a^2} +\frac{1}{b^2}-\frac{1}{c^2}= (5+\frac{1}{c} -\frac{2}{ab} )$....(3) (1)+(2)+(3); $\frac{1}{a^2} +\frac{1}{b^2}+\frac{1}{c^2} = 12+(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}) -2(\frac{1}{bc} +\frac{1}{ac}+\frac{1}{ab})$....(4) ¨Ò¡$(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})^2= \frac{1}{a^2} +\frac{1}{b^2}+\frac{1}{c^2}+2(\frac{1}{bc} +\frac{1}{ac}+\frac{1}{ab})$.............(5) á·¹(4)ŧã¹(5) $(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})^2=12+(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})$ ãËé$(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}) =m$ á¡éÊÁ¡ÒÃ$m^2-m-12=0$ä´é¤èÒ$m =4,-3$ ⨷Âì¡Ó˹´ãËé$a,báÅÐc$à»ç¹¨Ó¹Ç¹¨ÃÔ§ºÇ¡ ´Ñ§¹Ñé¹$m$·Õèãªéä´é¤×Í $4$ $(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}) =4$ ´Ñ§¹Ñé¹$(\frac{1}{a}+\frac{1}{b})=4-\frac{1}{c}$ $(\frac{1}{b}+\frac{1}{c})=4-\frac{1}{a}$ $(\frac{1}{a}+\frac{1}{c})=4-\frac{1}{b}$ $(\frac{1}{b} +\frac{1}{c})^2 -\frac{1}{a} -\frac{1}{a^2}= 3$ $(\frac{1}{a} +\frac{1}{c})^2 -\frac{1}{b} -\frac{1}{b^2}= 4$ $(\frac{1}{a} +\frac{1}{b})^2 -\frac{1}{c} -\frac{1}{c^2}= 5$ ¹ÓÁÒá·¹¤èÒã¹ÊÒÁÊÁ¡ÒùÕé¨Ðä´éÇèÒ $13a=9 , 14b=9+\frac{1}{3} ,15c=12+\frac{3}{11} $ $13a+14b+15c = 30\frac{20}{33} $.......¤Ô´¤èÒ$b$¼Ô´...·èÒ¹ä«â¤Å¹ªèÇÂà©ÅÂáÅéǤÃѺ µÒÁ¹Õé¤ÃѺ ªèǧ¹ÕéÊÁͧàºÅͨѴ¤ÃѺ ¢ÍÍÀÑ´éǤÃѺ ÍéÒ§ÍÔ§:
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"¶éÒàÃÒÅéÁºèÍÂæ ã¹·ÕèÊØ´àÃÒ¨ÐÃÙéÇèÒ¶éÒ¨ÐÅéÁ ÅéÁ·èÒä˹¨Ðà¨çº¹éÍ·ÕèÊØ´ áÅÐÃÙéÍÕ¡ÇèÒµèÍä»·ÓÂѧ䧨ÐäÁèãËéÅéÁÍÕ¡ ´Ñ§¹Ñ鹨§ÍÂèÒ¡ÅÑÇ·Õè¨ÐÅéÁ"...ÍÒ¨ÒÃÂìÍӹǠ¢¹Ñ¹ä·Â ¤ÃÑé§áá㹪ÕÇÔµ·ÕèÊͺ¤³ÔµÊÁÒ¤Á¤³ÔµÈÒʵÃìàÁ×èÍ»Õ2533...¼Áä´éá¤è24¤Ðá¹¹(¨Ò¡ÃéͤÐá¹¹) 24 ÁÕ¹Ò¤Á 2010 13:19 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ ¡ÔµµÔ |
#15
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ÍéÒ§ÍÔ§:
$P(2)=7(2)+8$ $P(3)=7(3)+8$ $P(4)=7(4)+8$ $p(5)=7(5)+8$ $P(6)=7(6)+8$ ´Ñ§¹Ñé¹ $$P(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)+7x+8$$ $$p(7)=6(5)(4)(3)(2)(1)+49+8=720+57=777$$ Ẻ¹Õ餧äÁè¶Ö¡¹Ð¤ÃѺ
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à§Ô¹«×éͼÁäÁèä´é(¶éÒäÁèÁÒ¡¾Í) |
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