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#1
30 ÁÕ¹Ò¤Á 2001, 16:17
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⨷Âì Antilog
1. Antilog ¢Í§ 8 log 2 - log 129 ÁÕ¤èÒà·èÒäÃ
1. (2-1/(2+1)).(2-1/(2^2+1)).(2-1/(2^3+1)).(2-1/(2^4+1)).(2-1/(2^5+1)).(2-1/(2^6+1)).(2+1/(2^7+1)) 2. (2+1/(2-1)).(2+1/(2^2-1)).(2+1/(2^3-1)).(2+1/(2^4-1)).(2+1/(2^5-1)).(2+1/(2^6-1)).(2+1/(2^7-1)) 3. (1+1/(2-1)).(1+1/(2^2-1)).(1+1/(2^3-1)).(1+1/(2^4-1)).(1+1/(2^5-1)).(1+1/(2^6-1)).(1+1/(2^7-1)) 4. (1+1/(2+1)).(1+1/(2^2+1)).(1+1/(2^3+1)).(1+1/(2^4+1)).(1+1/(2^5+1)).(1+1/(2^6+1)).(1+1/(2^7+1)) 
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#2
30 ÁÕ¹Ò¤Á 2001, 16:17
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ãËé N = Antilog( 8log 2 - log 129)
´Ñ§¹Ñé¹ log N = 8 log2 - log 129 = log (2^8 / 129 ) ´Ñ§¹Ñé¹ N = 2^8 / 129 àÁ×è;ԨÒóҢéÍ 4. ¤×Í (4/3)(6/5)(10/9)(18/17)(34/33)(66/65)(130/129) ¨Ðä´éà·èҡѺ 2 ^8 / 129 ´Ñ§¹Ñ鹵ͺ ¢éÍ 4. ¤ÃѺ
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#3
30 ÁÕ¹Ò¤Á 2001, 16:18
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