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#1
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#2
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$n(S) = \binom{10}{3} = 120$ ÇÔ¸Õ
ãËé E = à˵ءÒóì·ÕèËÂÔºä´éºÍÅÊÕ¢ÒÇÍÂèÒ§¹éÍ 2 ÅÙ¡ ¡Ã³Õ 1: ä´éÊÕ¢ÒÇ 2 ÅÙ¡ áÅÐÊÕÍ×è¹ æ 1 ÅÙ¡ -> ËÂÔºä´é $= \binom{4}{2}\binom{6}{1}= 36$ ÇÔ¸Õ ¡Ã³Õ 2: ä´éÊÕ¢ÒÇ 3 ÅÙ¡ -> ËÂÔºä´é $= \binom{4}{3}= 4$ ÇÔ¸Õ ´Ñ§¹Ñé¹ $n(E) = 36+4 = 40$ ÇÔ¸Õ $P(E) = \frac{40}{120}= \frac{1}{3} $ µÍº¢éÍ 1. |
#3
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ÍéÒ§ÍÔ§:
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