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Old 19 ¾ÄÉÀÒ¤Á 2012, 23:50
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ÃéÒ¹ÍÒËÒÃáËè§Ë¹Ö觾ºÇèÒ ÅÙ¡¤éÒà¢éÒÁÒÃѺ»ÃзҹÍÒËÒ÷ÕèÃéÒ¹«Öè§ÁÕ¡ëÇÂàµÕëÂǡѺÍÒËÒõÒÁÊÑè§à»ç¹´Ñ§¹Õé ÁÕ¼ÙéÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇ 28% ÁÕ¼ÙéÃѺ»ÃзҹÍÒËÒõÒÁÊÑè§ 40% ÁÕ¼ÙéäÁèÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇáÅÐäÁèÃѺ»ÃзҹÍÒËÒõÒÁÊÑè§à¾Õ§à¢éÒÁÒ´×èÁà¤Ã×èͧ´×èÁÀÒÂã¹ÃéÒ¹ 42% ¶éÒÁÕ¼ÙéÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇáÅÐÍÒËÒõÒÁÊÑè§ 30 ¤¹ ÁÕÅÙ¡¤éÒÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇ¡Õ褹
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19 ¾ÄÉÀÒ¤Á 2012 23:58 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ ~VesCuLaR~
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #2  
Old 20 ¾ÄÉÀÒ¤Á 2012, 00:07
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$p(A)$ ¤ÇÒÁ¹èÒ¨Ðà»ç¹·ÕèÁÕ¼Ùé·Ò¹¡êÇÂàµÕëÂÇ

$p(B)$ ¤ÇÒÁ¹èÒ¨Ðà»ç¹·ÕèÁÕ¼Ùé·Ò¹ÍÒËÒõÒÁÊÑè§

ÁÕ¼ÙéäÁèÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇáÅÐäÁèÃѺ»ÃзҹÍÒËÒõÒÁÊÑè§à¾Õ§à¢éÒÁÒ´×èÁà¤Ã×èͧ´×èÁÀÒÂã¹ÃéÒ¹ 42% áÊ´§ÇèÒ

$p(A\cup B)^' = 0.42$

´Ñ§¹Ñé¹

$p(A\cup B) = 0.58$

¨Ò¡

$p(A\cup B) = p(A) + p(B) - p(A\cap B)$

$0.58 = 0.28 + 0.4 - p(A\cap B)$

$p(A\cap B) = 0.1$

$0.1 = 30$ ¤¹

´Ñ§¹Ñé¹ $0.28 = 84$ ¤¹
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #3  
Old 20 ¾ÄÉÀÒ¤Á 2012, 00:10
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