#1
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ªèÇ·Õè¤ÃѺ ૵
ÃéÒ¹ÍÒËÒÃáËè§Ë¹Ö觾ºÇèÒ ÅÙ¡¤éÒà¢éÒÁÒÃѺ»ÃзҹÍÒËÒ÷ÕèÃéÒ¹«Öè§ÁÕ¡ëÇÂàµÕëÂǡѺÍÒËÒõÒÁÊÑè§à»ç¹´Ñ§¹Õé ÁÕ¼ÙéÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇ 28% ÁÕ¼ÙéÃѺ»ÃзҹÍÒËÒõÒÁÊÑè§ 40% ÁÕ¼ÙéäÁèÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇáÅÐäÁèÃѺ»ÃзҹÍÒËÒõÒÁÊÑè§à¾Õ§à¢éÒÁÒ´×èÁà¤Ã×èͧ´×èÁÀÒÂã¹ÃéÒ¹ 42% ¶éÒÁÕ¼ÙéÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇáÅÐÍÒËÒõÒÁÊÑè§ 30 ¤¹ ÁÕÅÙ¡¤éÒÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇ¡Õ褹
ãªè84¤¹ËÃ×Í»ÅèÒǤÃѺ 19 ¾ÄÉÀÒ¤Á 2012 23:58 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ ~VesCuLaR~ |
#2
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$p(A)$ ¤ÇÒÁ¹èÒ¨Ðà»ç¹·ÕèÁÕ¼Ùé·Ò¹¡êÇÂàµÕëÂÇ
$p(B)$ ¤ÇÒÁ¹èÒ¨Ðà»ç¹·ÕèÁÕ¼Ùé·Ò¹ÍÒËÒõÒÁÊÑè§ ÁÕ¼ÙéäÁèÃѺ»Ãзҹ¡ëÇÂàµÕëÂÇáÅÐäÁèÃѺ»ÃзҹÍÒËÒõÒÁÊÑè§à¾Õ§à¢éÒÁÒ´×èÁà¤Ã×èͧ´×èÁÀÒÂã¹ÃéÒ¹ 42% áÊ´§ÇèÒ $p(A\cup B)^' = 0.42$ ´Ñ§¹Ñé¹ $p(A\cup B) = 0.58$ ¨Ò¡ $p(A\cup B) = p(A) + p(B) - p(A\cap B)$ $0.58 = 0.28 + 0.4 - p(A\cap B)$ $p(A\cap B) = 0.1$ $0.1 = 30$ ¤¹ ´Ñ§¹Ñé¹ $0.28 = 84$ ¤¹ |
#3
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·íÒäÁÅÙ¡¤éÒÃéÒ¹¹ÕéàÂÍШѧ ¼Á¡çä´é84¤ÃѺ
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