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µÑé§ËÑÇ¢éÍãËÁè Reply
 
à¤Ã×èͧÁ×ͧ͢ËÑÇ¢éÍ ¤é¹ËÒã¹ËÑÇ¢é͹Õé
  #1  
Old 19 àÁÉÒ¹ 2008, 22:37
Bo_ok Bo_ok äÁèÍÂÙèã¹Ãкº
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ᡵÑÇ»ÃСͺ

¢éÍ 1 (a-b)(a+b)^3 - a^4 + b^4
________________________

¢éÍ 2 9a^2 - b^2 - 36c^2 - 12a + 12bc + 4
____________________

¢éÍ3 25 - a^2 - 4b^2 + b
________________________
¢éÍ 4 lxl^2 - 3lxl + 2 =?
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¢éÍ 5 3lx+1l^2 + 4lx+1l - 4 =?
________________________

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20 àÁÉÒ¹ 2008 17:04 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ nongtum
à˵ؼÅ: double post
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #2  
Old 19 àÁÉÒ¹ 2008, 23:33
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James007 James007 äÁèÍÂÙèã¹Ãкº
¨ÍÁÂØ·¸ì˹éÒË¡
 
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¢éÍ 1 $2ab(a-b)(a+b)$
¢éÍ 4 $(\left|\,x\right|-2)(\left|\,x\right|-1)$
¢éÍ 5 $(3\left|\,x+1\right|-2)(\left|\,x+1\right|+2)$
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #3  
Old 20 àÁÉÒ¹ 2008, 09:39
ÇÔË¡'s Avatar
ÇÔË¡ ÇÔË¡ äÁèÍÂÙèã¹Ãкº
ÅÁ»ÃÒ³ºÃÔÊØ·¸Ôì
 
Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 28 ¡Ã¡®Ò¤Á 2007
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Default ¢éͤÇÒÁà´ÔÁ¢Í§¤Ø³ Bo_ok

ã¤ÃÁÕ⨷Âìà¾ÔèÁàµÔÁà¡ÕèÂǡѺ¡ÒÃᡵÑÇ»ÃСͺÃèÇÁ
¡ÒÃâÍà»ÍàêÑè¹
¼ÅµèÒ§¡ÓÅѧ2
¡ÓÅѧ2 ÊÁºÙÃ³ì ¢Í˹è͹ФÐ
àÍÒÂÒ¡æ¹Ð áÅЪèǺ͡ÇÔ¸Õ¤Ô´´éǤèÐ ¢Íº¤Ø³ÁÒ¡¤èÐ[/quote]

1.¨§á¡µÑÇ»ÃСͺ¢Í§
$(x-y)^{3}$+$(y-z)^{3}$+$(z-x)^{3}$
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #4  
Old 20 àÁÉÒ¹ 2008, 13:52
¹¹·ì's Avatar
¹¹·ì ¹¹·ì äÁèÍÂÙèã¹Ãкº
ËÑ´à´Ô¹ÅÁ»ÃÒ³
 
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àËç¹ä´éªÑ´ÇèÒ $(x−y) +(y−z) +(z−x) = 0$
à¾ÃÒЩйÑé¹ $(x−y)^3 +(y−z)^3 +(z−x)^3 = 3(x−y)(y−z)(z−x)$
__________________
..The answer to everything might be 42, but where's the question? ...
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #5  
Old 20 àÁÉÒ¹ 2008, 14:52
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¡ÃкÕèäÇ
 
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¢éÍ 2 ¢Í§¤Ø³ Bo_ok ¤ÃѺ
\[\begin{array}{rcl}
9a^2-b^2-36c^2-12a+12bc+4&=&(9a^2-12a+4)-(b^2-12bc+36c^2)\\
&=&(3a-2)^2-(b-6c)^2\\
&=&(3a-2+b-6c)(3a-2-b+6c)\\
\end{array}\]$\therefore 9a^2-b^2-36c^2-12a+12bc+4=(3a+b-6c-2)(3a-b+6c-2)$
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #6  
Old 20 àÁÉÒ¹ 2008, 15:47
Anonymer Anonymer äÁèÍÂÙèã¹Ãкº
ËÑ´à´Ô¹ÅÁ»ÃÒ³
 
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àÍÒ⨷ÂìãËè¤èÐ ¡çà»ç¹â¨·Âì»Ò¹¡ÅÒ§¤èÐ áµè¡ç¹èÒʹ㨴չФÐ

1. ¨§á¡µÑÇ»ÃСͺ¢Í§ $$(a+b+c)^4-(a+b)^4-(b+c)^4-(c+a)^4+a^4+b^4+c^4$$

**¢é͹ÕéäÁè¨Óà»ç¹µéͧ¡ÃШÒ¤èÐÁͧ´Õæ¤èÐ Å᷹ͧ $P(a,b,c)=> P(a,0,0),P(0,b,0),P(0,0,c)$ áÅéǨÐä´éàͧ¤èÐ

àÊÃÔÁãËéÍÕ¡¢éͤèÐ §èÒÂæ

2.)ãËé $P(x)$ à»ç¹¾ËعÒÁ´Õ¡ÃÕ 2008 «Öè§ÊÑÁ»ÃÐÊÔ·¸Ôì $x^{2008}$ à»ç¹ 1 áÅÐ $P(2007)=0,P(2006)=1,...,P(1)=2006,P(0)=2007$
áÅéǨ§ËÒ¤èҢͧ $P(2008)$

20 àÁÉÒ¹ 2008 17:05 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ nongtum
à˵ؼÅ: double post
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #7  
Old 21 àÁÉÒ¹ 2008, 20:19
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kanakon kanakon äÁèÍÂÙèã¹Ãкº
ºÑ³±Ôµ¿éÒ
 
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ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ Anonymer View Post

2.)ãËé $P(x)$ à»ç¹¾ËعÒÁ´Õ¡ÃÕ 2008 «Öè§ÊÑÁ»ÃÐÊÔ·¸Ôì $x^{2008}$ à»ç¹ 1 áÅÐ $P(2007)=0,P(2006)=1,...,P(1)=2006,P(0)=2007$
áÅéǨ§ËÒ¤èҢͧ $P(2008)$
$$P(x)=(x)(x-1)(x-2)...(x-2007)+(2007-x)$$
__________________
¤ Ç Ò Á ÃÑ º ¼Ô ´ ª Í º

$$|I-U|\rightarrow \infty $$
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #8  
Old 21 àÁÉÒ¹ 2008, 21:41
Bo_ok Bo_ok äÁèÍÂÙèã¹Ãкº
ÊÁÒªÔ¡ãËÁè
 
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¢Íº¤Ø³¹êÒ¤êÒ
ã¤Ãà¾ÔèÁàµÔÁÍÕ¡¡çªèÇÂá¡é ªèÇÂ͸ԺÒÂ˹è͹ФÐ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #9  
Old 23 àÁÉÒ¹ 2008, 20:49
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ÅÁ»ÃÒ³ºÃÔÊØ·¸Ôì
 
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ÇÔ¸Õ·Ó¢éÍ1.¹Ð¤ÃѺ
$(a-b)(a+b)^3-a^4+b^4=(a-b)(a+b)^3-(a^3-b^3)=(a-b)(a^3+3a^2b+3ab^2+b^3)-(a-b)(a^3+a^2b+ab^2+b^3)=(a-b)(2a^2b+2ab^2)=2ab(a-b)(a+b)$
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µÐ»Ù·ÕèµÍ¡º¹á¼è¹äÁé áÁé¶Í¹ÍÍ¡Âѧ¤§·Ôé§ÃÍÂäÇé
¤Ó¾Ù´·ÔèÁá·§¨Ôµã¨¤¹ ãÂÁÔãªèà»ç¹à©¡àªè¹à´ÕÂǡѹ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #10  
Old 23 àÁÉÒ¹ 2008, 21:00
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Aermig Aermig äÁèÍÂÙèã¹Ãкº
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¢éÍ 3. ¼Á¤Ô´ÇèÒäÁèÊÒÁÒöá¡ã¹ÃÙ»$(x_1a+x_2b+x_3)(y_1a+y_2b+y_3)$
â´Â·Õè $x_1,x_2,x_3,y_1,y_2,y_3$à»ç¹¨Ó¹Ç¹¨ÃÔ§ä´é (Íѹ¹Õé¼ÁÂѧäÁè¤èÍÂá¹è㨠áµè¼Á·ÓáÅéÇÁѹ¢Ñ´áÂ駤ÃѺ)
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µÐ»Ù·ÕèµÍ¡º¹á¼è¹äÁé áÁé¶Í¹ÍÍ¡Âѧ¤§·Ôé§ÃÍÂäÇé
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µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
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