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#16
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áÅéÇẺ¹ÕéÅèÐ ¼Ô´µÃ§ä˹
$-1 = -1$ $\frac{-1}{1} = \frac{1}{-1} $ $\sqrt{\frac{-1}{1}} = \sqrt{\frac{1}{-1} } $ $\frac{\sqrt{-1} }{\sqrt{1} } = \frac{\sqrt{1}} {\sqrt{-1}} $ $(\sqrt{1}\sqrt{-1})\frac{\sqrt{-1} }{\sqrt{1} } = (\sqrt{1}\sqrt{-1}) \frac{\sqrt{1}} {\sqrt{-1}} $ $\sqrt{-1} \sqrt{-1} = \sqrt{1} \sqrt{1} $ $(i)(i) = (1)(1)$ $i^2 = 1$ $-1 = 1$
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ÁÒËÒ¤ÇÒÁÃÙéäÇéµÔÇËÅÒ¹ áµèËÅÒ¹äÁèàÍÒàÅ¢áÅéÇ à¢éÒÁÒ·ÓàÅ¢àÍÒÁѹÍÂèÒ§à´ÕÂÇ ¤ÇÒÁÃÙéà»ç¹ÊÔè§à´ÕÂÇ·ÕèÂÔè§ãËé ÂÔè§ÁÕÁÒ¡ ÃÙéÍÐäÃäÁèÊÙé ÃÙé¨Ñ¡¾Í (¡àÇ鹤ÇÒÁÃÙé äÁèµéͧ¾Í¡çä´é ËÒäÇéÁÒ¡æáËÅдÕ) (áµè¡çÍÂèÒãËéÁÒ¡¨¹·èÇÁËÑÇ àÍÒµÑÇäÁèÃÍ´) |
#17
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ÍéÒ§ÍÔ§:
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#18
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áÅéÇÍѹ¹ÕéÅèФÃѺ
$x^4+x^3+x^2+x+1=0$ $x(x^3+x^2+x+1)+1=0$ $x^3+x^2+x+1=\frac{-1}{x}$ $x^4+\frac{-1}{x}=0$ $\frac{x^5-1}{x}=0$ $x=1$ ¼Ô´µÃ§ä˹ËÇèÒ
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My stAtUs ·ÓäÁÂÔè§àÃÕ¹ áÅéÇÂÔè§â§èËÇèÒÒ |
#19
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