#1
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͹ءÃÁ ??
$\frac{1+\frac{1}{3^2} +\frac{1}{5^2} + ....}{\frac{1}{2^2} +\frac{1}{4^2} +\frac{1}{6^2} +....}$ $= ?$
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#2
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let $s=\frac{1}{1^2}+\frac{1}{2^2}+\frac{1}{3^2}+...$...(7777)
¹Ó $\frac{1}{2^2}$ ¤Ù³·Ñé§ÊÁ¡Òà $\frac{s}{2^2}=\frac{1}{2^2}+\frac{1}{4^2}+\frac{1}{6^2}+...$....(2553) ¹Ó $(7777)-(2553)$ $\frac{3s}{4}=\frac{1}{1^2}+\frac{1}{3^2}+\frac{1}{5^2}+...$(2009) ¨Ò¡ $(2553),(2009)$ ¨Ðä´éÇèÒ $\frac{\frac{1}{1^2}+\frac{1}{3^2}+\frac{1}{5^2}+...}{\frac{1}{2^2}+\frac{1}{4^2}+\frac{1}{6^2}+...}$ =$\frac{\frac{3s}{4}}{\frac{s}{4}}$ =........ |
#3
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ÍéÒ§ÍÔ§:
»Å. »Õ¹Õé 2010 áÅéǹФÃѺ
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Fortune Lady
11 Á¡ÃÒ¤Á 2010 18:09 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ Siren-Of-Step |
#4
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