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ÊÁѤÃÊÁÒªÔ¡ ¤ÙèÁ×Í¡ÒÃãªé ÃÒª×èÍÊÁÒªÔ¡ »¯Ô·Ô¹ ¢éͤÇÒÁÇѹ¹Õé

µÑé§ËÑÇ¢éÍãËÁè Reply
 
à¤Ã×èͧÁ×ͧ͢ËÑÇ¢éÍ ¤é¹ËÒã¹ËÑÇ¢é͹Õé
  #1  
Old 30 ÁÕ¹Ò¤Á 2001, 17:14
<natt>
 
¢éͤÇÒÁ: n/a
Post ãËé¾Ç¡¾Õèæà©Å áÅк͡ÇÔ¸Õ¤Ô´ ãËé˹èͤÃѺ

1.máÅÐnà»ç¹¨Ó¹Ç¹àµçÁºÇ¡áÅéÇËÒôéÇÂ7áÅéÇàËÅ×ÍàÈÉ3áÅÐ5µÒÁÅӴѺ´Ñ§¹Ñé¹ m¡ÓÅѧ2-mn+n¡ÓÅѧÊͧ ¶Ù¡ËÒôéÇÂ7¨ÐàËÅ×ÍàÈÉà·èÒäÃ
2.x¤Ù³àÈÉ1Êèǹx=2 áÅéÇx¡ÓÅѧ3¤Ù³àÈÉ1Êèǹx¡ÓÅѧ3¨Ðà·èҡѺà·èÒäÃ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #2  
Old 30 ÁÕ¹Ò¤Á 2001, 17:14
<jamess>
 
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Post

m ËÒà 7 áÅéÇàËÅ×ÍàÈÉ 3 áÊ´§ÇèÒ m ÊÒÁÒöàªÕ¹ä´éã¹ÃÙ» m = 7a+3 ;a=0,1,2,...
n ËÒà 7 áÅéÇàËÅ×ÍàÈÉ 5 áÊ´§ÇèÒ n ÊÒÁÒöàªÕ¹ä´éã¹ÃÙ» n = 7b+5 ;b=0,1,2,...

m^2 - mn +n^2 = (7a+3)^2 - (7a+3)(7b+5) + (7b+5)^2
Ö1. Ö(7a+3)^2 = 7*7a^2 + 2*7*3*a +9 àÁ×èÍËÒôéÇ 7 ¨ÐàËÅ×ÍàÈÉ 2 (à¾ÃÒÐà·ÍÁÍ×è¹æ ÁÕ 7 à»ç¹µÑÇ»ÃСͺ áÅÐ 9/7 àËÅ×ÍàÈÉ 2 )
2. (7a+3)(7b+5) = 7*7*a*b + 3*7b + 5*7a + 15 àÁ×èÍËÒôéÇ 7 áÅéǨÐàËÅ×ÍàÈÉ 1 (15/7 àËÅ×ÍàÈÉ 1)
3. (7b+5)^2 = 7*7*b^2 + 2*5*7b + 25 àÁ×èÍËÒôéÇ 7 àËÅ×ÍàÈÉ 4 (25/7 àËÅ×ÍàÈÉ 4)
4. àÍÒàÈÉ·Õèä´éÁҺǡź¡Ñ¹
2 - 1 + 4 = 5
àÈɤ×Í 5
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #3  
Old 30 ÁÕ¹Ò¤Á 2001, 17:14
<natt>
 
¢éͤÇÒÁ: n/a
Post

¢Íº¤Ø³¤ÃѺ
àÍÒ¢éÍ2´éǤÃѺ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #4  
Old 30 ÁÕ¹Ò¤Á 2001, 17:15
<aaa>
 
¢éͤÇÒÁ: n/a
Post

¢éÍÊͧ⨷Âì¼Ô´ËÃ×Íà»ÅèÒ ¹èÒ¨Ðà»ç¹
x+1/x =2
áÅéÇ x^3 + 1/x^3 = ?
ÁÒ¡¡ÇèÒ¤ÃѺ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #5  
Old 30 ÁÕ¹Ò¤Á 2001, 17:15
<natt>
 
¢éͤÇÒÁ: n/a
Post

¢Íâ·É áËÐæ
ªèÇÂà©ÅÂ˹èǹÐ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #6  
Old 30 ÁÕ¹Ò¤Á 2001, 17:15
<12>
 
¢éͤÇÒÁ: n/a
Post

x+1/x=2
x+1=2x
x=1
x^3+1=1^3+1=2
1^3=1
x^3+1/x^3=2/1=2
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #7  
Old 06 ¾ÄÉÀÒ¤Á 2008, 20:50
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¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ <12> View Post
x+1/x=2
x+1=2x
x=1
x^3+1=1^3+1=2
1^3=1
x^3+1/x^3=2/1=2
·Ó¼Ô´àËÁ×͹¼ÁÊÁÑ¡è͹àÅ ¤Ô´äÁèÍÍ¡¡çàÅè¹Âѧ§ÕéàËÁ×͹¡Ñ¹¤Ñº 555+
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #8  
Old 06 ¾ÄÉÀÒ¤Á 2008, 21:06
Maphybich Maphybich äÁèÍÂÙèã¹Ãкº
¨ÍÁÂØ·¸ì˹éÒãËÁè
 
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¢Ø´ÁÒ·ÓäÁ¤ÃѺà¹ÕèÂÂÂ!!
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #9  
Old 06 ¾ÄÉÀÒ¤Á 2008, 23:24
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ÅÁ»ÃÒ³äÃéÊÀÒ¾
 
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ä˹æ¡ç¢Ø´ÁÒáÅéÇ ¨ÐªèÇÂá¡éãËé¡çáÅéǡѹÍФÃѺ
ÇÔ¸Õ·Õè 1. ¹Ó $x + \frac{1}{x} = 2$ ÁÒ¤Ù³´éÇ x áÅéǨÐä´é $x^2 + 1 = 2x$
¨Ñ´ÃÙ»ä´é $x^2- 2x + 1 = (x-1)^2 = 0$ ´Ñ§¹Ñ鹨Ðä´é x = 1 áÅéÇ $x^3+\frac{1}{x^3} = 2$ ¤ÃѺ

ÇÔ¸Õ·Õè 2. ¹Ó $x + \frac{1}{x} = 2$ ÁÒ¡¡ÓÅѧÊͧ¨Ðä´é $4 = x^2 + 2 + \frac{1}{x^2} $
áÅéÇź´éÇ 4 ¨Ðä´é $0 = x^2 - 2 + \frac{1}{x^2} = (x - \frac{1}{x})^2$ --> $x - \frac{1}{x} = 0$ áÅéÇä´é x = 1 àËÁ×͹¡Ñ¹¤ÃѺ

áµè ÊÓËÃѺ¡Ã³Õ $x + \frac{1}{x} = 5$ ÇÔ¸Õ·Õè 1.áÅÐ 2 äÁèàËÁÒзÕè¨ÐãªéËÒ¤èҢͧ $x^3 + \frac{1}{x^3}$ ÍФÃѺ

¤ÇÃãªé $x^3 + \frac{1}{x^3} = (x + \frac{1}{x})(x^2- 1 + \frac{1}{x^2})$ â´Â·Õè $(x^2- 1 + \frac{1}{x^2}) = (x + \frac{1}{x})^2 -3$

ËÃ×Í $x^3 + \frac{1}{x^3} = (x + \frac{1}{x})^3 - 3(x + \frac{1}{x})$ ¡çä´é¤ÓµÍº¡Ã³Õ¹Õéà»ç¹ 110 ¤ÃѺ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #10  
Old 07 ¾ÄÉÀÒ¤Á 2008, 08:31
¤usÑ¡¤³Ôm's Avatar
¤usÑ¡¤³Ôm ¤usÑ¡¤³Ôm äÁèÍÂÙèã¹Ãкº
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ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ Maphybich View Post
¢Ø´ÁÒ·ÓäÁ¤ÃѺà¹ÕèÂÂÂ!!
à¡èÒ¢¹Ò´¹Ñé¹àÅÂËÃÍà¹ÕèÂ
__________________
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #11  
Old 07 ¾ÄÉÀÒ¤Á 2008, 13:24
mathematiiez's Avatar
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¡ÃкÕè»ÃÐÊÒ¹ã¨
 
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