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  #1  
Old 01 ¡ØÁÀҾѹ¸ì 2016, 02:14
smepyoheeee smepyoheeee äÁèÍÂÙèã¹Ãкº
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Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 09 àÁÉÒ¹ 2013
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Default ͹ءÃÁ á¤Å2 ¤ÃѺ(ËÒÅÙèà¢éÒ/ÍÍ¡)

$ \sum_{n = 1}^{\infty}( \frac{n+2}{n} )^n $ ÅÙèà¢éÒËÃ×ÍÅÙÍÍ¡
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  #2  
Old 01 ¡ØÁÀҾѹ¸ì 2016, 09:56
nooonuii nooonuii äÁèÍÂÙèã¹Ãкº
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ÅÙèÍÍ¡¤ÃѺ ãªé¡Ò÷´Êͺ¡ÒÃÅÙèÍÍ¡ä´é
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site:mathcenter.net ¤Ó¤é¹
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  #3  
Old 01 ¡ØÁÀҾѹ¸ì 2016, 19:10
smepyoheeee smepyoheeee äÁèÍÂÙèã¹Ãкº
àÃÔèÁ½Ö¡ÇÃÂØ·¸ì
 
Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 09 àÁÉÒ¹ 2013
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¢Íº¤Ø³ÁÒ¡æ¤ÃѺ
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  #4  
Old 04 ÊÔ§ËÒ¤Á 2016, 05:01
XIIIX XIIIX äÁèÍÂÙèã¹Ãкº
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root test¤ÃѺ
ρ=limsup (n+2)/n as n goes to inf is 1 thus diverges

ËÃ×ÍäÁè¡çÅͧ¾Ô¨ÒÃ³Ò ((n+2)/n)^n ¤ÃѺ ¨ÐàËç¹ÇèÒà·èҡѺ (1+ 2/n)^n=1+....+(2/n)^n ´Ùá¤è1 µÑÇáá ¨ÐàËç¹ÇèÒ·Ø¡æpartial sum¨ÐÁÕ1ÍÍ¡ÁÒ 1ºÇ¡¡Ñ¹à»ç¹Í¹Ñ¹µì¡çµéͧdivergesá¹è¹Í¹¤ÃѺ
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Mathematics, rightly viewed possesses not only truth, but supreme beauty. B.R.
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