#1
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ªèÇ´éǤèÐ
$¡ÒÃËҨӹǹµÑÇ»ÃСͺ àªè¹ 24=(2^3)(3^1) ÇÔ¸ÕËÒ ¤×Í àÍÒ (3+1)(1+1) = 8 µÑÇ$
ÍÂÒ¡·ÃÒºÇèÒ·ÓäÁ¶Ö§¤Ô´áºº¹Õéä´é¤Ð 21 ÁԶعÒ¹ 2014 19:36 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ shiro40 |
#2
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ÍéÒ§ÍÔ§:
µÑÇ»ÃСͺäÁèÁÕ 2 à»ç¹µÑÇ»ÃСͺ ËÃ×Í µÑÇ»ÃСͺÁÕ 2 à»ç¹µÑÇ»ÃСͺµÑÇà´ÕÂÇ ËÃ×Í µÑÇ»ÃСͺÁÕ 2 à»ç¹µÑÇ»ÃСͺÊͧµÑÇ ËÃ×Í µÑÇ»ÃСͺÁÕ 2 à»ç¹µÑÇ»ÃСͺÊÒÁµÑÇ ÁÕ 4 Ẻ(3+1) µÑÇ»ÃСͺäÁèÁÕ 3 à»ç¹µÑÇ»ÃСͺ ËÃ×Í µÑÇ»ÃСͺÁÕ 3 à»ç¹µÑÇ»ÃСͺµÑÇà´ÕÂÇ ÁÕ 2 Ẻ(1+1) µÑÇ»ÃСͺÁÕ 4*2 = 8 ÇÔ¸Õ ¶éÒäÁèà¢éÒã¨Åͧ¶ÒÁ¤¹Í×è¹´Ù¤ÃѺ |
#3
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ÍéÒ§ÍÔ§:
$1 = 2^0\cdot 3^0\\ 2 = 2^1\cdot 3^0$ $3 = 2^0\cdot 3^1\\ 4=2^2\cdot 3^0$ $6 = 2^1\cdot 3^1 \\ 8 = 2^3\cdot 3^0$ $12=2^2\cdot 3^1 \\ 24=2^3\cdot 3^1$ $«Öè§Êѧࡵä´éÇèÒ 2^3 ÁÕµÑÇ»ÃСͺ¤×Í 2^0 , 2^1 , 2^2 áÅÐ 2^3 ÁÕ·Ñé§ËÁ´ 3+1 = 4 ¨Ó¹Ç¹$ $3^1 ÁÕµÑÇ»ÃСͺ¤×Í 3^0 áÅÐ 3^1 ÁÕ·Ñé§ËÁ´ 1+1 = 2 ¨Ó¹Ç¹$ $´Ñ§¹Ñé¹ 24=2^3\cdot 3^1 ÁÕµÑÇ»ÃСͺ·Ñé§ËÁ´ (3+1)(1+1) = 8 ¨Ó¹Ç¹$
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#4
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à¹×èͧ¨Ò¡ $24 = 2^3×3^1$
´Ñ§¹Ñé¹µÑÇ»ÃСͺ¢Í§ 24 ¨ÐÍÂÙèã¹ÃÙ» $2^n×3^m$ â´Â·Õè n=0, 1, 2, 3 (ÁÕ 4 Ẻ) áÅÐ m=0, 1(ÁÕ 2 Ẻ) ¨Ö§ÁաóշÕèà¡Ô´¢Öé¹ä´é·Ñé§ËÁ´ 4×2 = 8 ¡Ã³Õ |
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