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Old 25 ¡Ã¡®Ò¤Á 2013, 19:15
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Old 25 ¡Ã¡®Ò¤Á 2013, 19:40
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Old 26 ¡Ã¡®Ò¤Á 2013, 18:08
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Old 26 ¡Ã¡®Ò¤Á 2013, 20:24
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(Learning through Problem Solving ) ¤×ÍàÃÒ¨ÐäÁèà¹é¹à¹×éÍËÒ¾×é¹°Ò¹·ÕèÂÒÇ仹ѡ

áµè¾ÍÊ͹à¹×éÍËҵç¹Õé¹Ô´Ë¹èÍ àÃÒ¡ç¨Ð⹻ѭËÒãËé·Ó¤ÃѺ ÇèÒ¨Ò¡·Õèà¾Ôè§àÃÕ¹仹Õè

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ÍÂèÒ§ÊÁÁµÔÇèÒ ¶éÒàÃÕ¹µÃÕ⡳ÁÔµÔàÃ×èͧÊÙµÃÁØÁ 3 à·èÒ ¡çÍÒ¨¨Ð¡µÑÇÍÂèÒ§àªè¹ ä˹Åͧ¾ÔÊÙ¨¹ìÊÔÇèÒ

$\cos 3A = 4\cos A \cos(60^{\circ} - A) \cos(60^{\circ}+ A)$

$\sin 3A = 4\sin A \sin(60^{\circ} - A) \sin(60^{\circ}+ A)$

$\tan 3A = \tan A \tan(60^{\circ} - A) \tan(60^{\circ}+ A)$

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$(1-4\sin^2 9^{\circ})(1-4\sin^2 27^{\circ})(1-4\sin^2 81^{\circ})(1-4\sin^2 243^{\circ})=?$

$(1+\frac{2\cos\frac{\pi}{7}}{\cos\frac{3\pi}{7}})(1+\frac{2\cos\frac{2\pi}{7}}{\cos\frac{6\pi}{7}})(1+\frac{2\cos\frac{3\pi}{7} }{\cos\frac{6\pi}{7}})=?$

¨ÐãËé´Õ¤ÇèÐÊ͹ÁØÁÁͧ¢Í§¤¹ÊÃéҧ⨷Âì´éǤÃѺ ¨Ðä´éʹءʹҹ¡ÇèÒà´ÔÁ

26 ¡Ã¡®Ò¤Á 2013 20:26 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ gon
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