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ÊÁѤÃÊÁÒªÔ¡ ¤ÙèÁ×Í¡ÒÃãªé ÃÒª×èÍÊÁÒªÔ¡ »¯Ô·Ô¹ ¢éͤÇÒÁÇѹ¹Õé

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  #1  
Old 31 ¾ÄÉÀÒ¤Á 2015, 10:14
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Default ÊÁ¡Òá¡ÓÅѧ x

$$\sqrt{(2+\sqrt{3}})^x + \sqrt{(2-\sqrt{3}})^x = 2^x$$

ãªéÇÔ¸Õá·¹¤èÒ¨Ðä´é¤ÓµÍº x = 2 áµè¶éÒ¨ÐËҤӵͺâ´Â¡ÒÃá¡éÊÁ¡Òèеéͧ·ÓÍÂèÒ§äà ªèÇÂá¹Ð¹Ó´éǤÃѺ
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  #2  
Old 31 ¾ÄÉÀÒ¤Á 2015, 11:59
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FranceZii Siriseth FranceZii Siriseth äÁèÍÂÙèã¹Ãкº
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ÇÒ´¡ÃÒ¿´Ù¤ÃѺ ºÍ¡ä´éÇèÒÁդӵͺà´ÕÂÇ
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  #3  
Old 31 ¾ÄÉÀÒ¤Á 2015, 12:09
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¡¢£¤¥¦§ ¡¢£¤¥¦§ äÁèÍÂÙèã¹Ãкº
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http://www.mathcenter.net/forum/showthread.php?t=22520
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  #4  
Old 31 ¾ÄÉÀÒ¤Á 2015, 18:56
»ÃÐàÇÈ »ÃÐàÇÈ äÁèÍÂÙèã¹Ãкº
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