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  #1  
Old 26 àÁÉÒ¹ 2010, 01:29
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ÁÕ⨷Âì¢é͹֧ÁÒ¶ÒÁ¤ÃѺÅͧ´Ù¡Ñ¹
¼ÅÊÓàÃ稢ͧ 5-\frac{1}{2-\frac{1}{2-\frac{1}{2-...} } } ÁÕ¤èÒà·èҡѺà·èÒã´

1. 3 2. 3\frac{1}{2} 3. 4 4. 4\frac{1}{2}
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  #2  
Old 26 àÁÉÒ¹ 2010, 01:41
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µéͧ¢Íâ·É´éǹФÃѺÁ×ÍãËÁèËÑ´·Óà´ÕÂǾÔÁ¾ìãËÁèáÅéǡѹ
¼ÅÊÓàÃ稢ͧ 5-$\frac{1}{2-\frac{1}{2-\frac{1}{2-...} } }$ ÁÕ¤èÒà·èҡѺà·èÒã´

1)3 2) 3$\frac{1}{2}$ 3) 4 4) 4$\frac{1}{2}$
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  #3  
Old 26 àÁÉÒ¹ 2010, 02:00
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µÍº¢éÍ 3 - -a
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  #4  
Old 26 àÁÉÒ¹ 2010, 08:16
banker banker äÁèÍÂÙèã¹Ãкº
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ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ ¤ÇÒÁ½Ñ¹ View Post
µéͧ¢Íâ·É´éǹФÃѺÁ×ÍãËÁèËÑ´·Óà´ÕÂǾÔÁ¾ìãËÁèáÅéǡѹ
¼ÅÊÓàÃ稢ͧ 5-$\frac{1}{2-\frac{1}{2-\frac{1}{2-...} } }$ ÁÕ¤èÒà·èҡѺà·èÒã´

1)3 2) 3$\frac{1}{2}$ 3) 4 4) 4$\frac{1}{2}$
let $\frac{1}{2-\frac{1}{2-\frac{1}{2-...} } } = x$

$\frac{1}{2-x } = x$

$x^2 -2x+1 =0$

$(x-1)^2 =0$

$x=1$



5-$\frac{1}{2-\frac{1}{2-\frac{1}{2-...} } } = 5 - 1 =4$
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