#1
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ÊÁ¡ÒáÓÅѧ2
¨§á¡éÃкºÊÁ¡Òà x - 2y=4 áÅÐ x^2 - y^2 =1
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#2
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$x-2y=4$--->$x=2y+4$------(1)
$x^2-y^2=1$----(2) á·¹ (1) ã¹ (2) $(2y+4)^2-y^2=1$ $4y^2+16y+16-y^2=1$ $3y^2+16y+15=0$ $y=\frac{-8\pm\sqrt{19}}{3}$ $x=\frac{-4\pm2\sqrt{19}}{3}$
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¤³ÔµÈÒʵÃì ¤×Í ÀÒÉÒÊÒ¡Å ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁÊǧÒÁ ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁ¨ÃÔ§ µÔ´µÒÁªÁ¤ÅÔ»ÇÕ´ÕâÍä´é·Õèhttp://www.youtube.com/user/poperKM 21 µØÅÒ¤Á 2013 23:21 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ poper |
#3
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¨Ò¡ÊÁ¡ÒÃááä´é x=2y+4 áÅéÇá·¹ä»ã¹ÊÁ¡Ò÷ÕèÊͧ¤ÃѺ
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#4
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¢Íº¤Ø³ ¤Ø³popper ¡Ñº¤Ø³¹¡¡ÃÐàµç¹»Ñ¡ËÅÑ¡ ¹Ð¤èÐ ~^^
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ÊÙéµèÍä»àÃ×èÍÂæ àÃÒäÁèàÁ×èÍ àÃÒäÁèà˹×èÍ 21 µØÅÒ¤Á 2013 23:14 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ my melody |
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