#1
|
|||
|
|||
⨷ÂìµÃÕ⡹ÁÔµÔ
$4sin^2x - 6tanx + 2sec^2x = 0$
$â´Â·Õè 0 < x < \frac{\pi }{2} $ $¤èҢͧ tan( \frac{\pi }{3} + x) à×·èҡѺà·èÒäÃ$ |
#2
|
||||
|
||||
Hint:
1.$tanx=\frac{sinx}{cosx} =sinxsecx$ 2.Áͧ $sinx=A,secx=B$ áÅéÇá¡éÊÁ¡ÒÃ
__________________
I am _ _ _ _ locked |
#3
|
|||
|
|||
$¡Ó˹´ãËé sinA - sin2A + sin3A = 0 â´Â·Õè 0 < A < \frac{\pi }{2} áÅéÇ tanA - tan2A +tan3A ¨ÐÁÕ¤èÒà·èÒã´$
|
#4
|
||||
|
||||
¢é͹Õé¡ç¡ÃШÒ sin2A,sin3A áÅéÇá¡éÊÁ¡ÒÃËÒAä´éáÅéÇ
__________________
I am _ _ _ _ locked |
|
|