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Old 09 ¡Ñ¹ÂÒ¹ 2012, 20:27
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¶éÒ $arcsin\frac{4x}{\sqrt{1+16x^2}}+arccos\frac{1}{\sqrt{1+4x^2}}+arctan x = 0$ áÅéǤèÒ x ·Õèà»ç¹ºÇ¡ÁÕ¤èÒà·èÒã´

11 ¡Ñ¹ÂÒ¹ 2012 21:19 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 5 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ -Math-Sci-
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Old 13 ¡Ñ¹ÂÒ¹ 2012, 11:07
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gon gon äÁèÍÂÙèã¹Ãкº
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¶éÒ $arcsin\frac{4x}{\sqrt{1+16x^2}}+arccos\frac{1}{\sqrt{1+4x^2}}+arctan x = 0$ áÅéǤèÒ x ·Õèà»ç¹ºÇ¡ÁÕ¤èÒà·èÒã´
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à¾ÃÒÐÇèÒ¶éÒ $x>0$ áÅéǤèҢͧ arcsin, arccos, arctan ¢Í§áµèÅо¨¹ìÁÕ¤èÒà»ç¹ºÇ¡·Ø¡¤èÒ

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Old 13 ¡Ñ¹ÂÒ¹ 2012, 17:26
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