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Old 26 àÁÉÒ¹ 2012, 09:14
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$ \ \ 31 \ 41 \ 59 \ 26 \ 53 \ ..$
what is the next two digits ?

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Old 26 àÁÉÒ¹ 2012, 11:35
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¢éÍáá à»ç¹àŢⴴáµèÅÐËÅÑ¡¢Í§¤èÒ $\pi$
¢éÍÊͧ à´ÒÇèÒ $= \pi$ ¤ÃѺ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #3  
Old 26 àÁÉÒ¹ 2012, 11:44
artty60 artty60 äÁèÍÂÙèã¹Ãкº
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¢éÍ1 ?58

¢éÍ2 ?0 ãªè¤èÒ$\pi $¨ÃÔ§´éÇ ã¤Ã¨ÐªèÇÂáÊ´§ÇÔ¸Õ¾ÔÊÙ¨¹ìãËé´Ù˹èÍÂä´éÁÑê¤ÃѺ¢é͹Õé

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26 àÁÉÒ¹ 2012 12:11 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 2 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ artty60
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Old 26 àÁÉÒ¹ 2012, 16:36
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¢éÍ1.⪤´Õ·Õè¼Áà¤Â¨ÓàÅè¹ 3.141592653523846...
¢éÍ2·ÓäÁèà»ç¹

ÍéÒǼÁá»é¡ µéͧà»ç¹áºº¤Ø³artty
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26 àÁÉÒ¹ 2012 22:44 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 2 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ polsk133
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Old 26 àÁÉÒ¹ 2012, 17:13
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à·¾àÇÍÃì ⨷ÂìäÁè«ÕàÃÕÂÊàÅÂÍèÐ áÎèæ à˹áÅéǢͪÔè§
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Old 26 àÁÉÒ¹ 2012, 19:23
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¤Ò´äÁè¶Ö§¨ÃÔ§æ -*- ÃÍÂËÂÑ¡¢Í§¼ÁÂѧ¹é͹ѡ

26 àÁÉÒ¹ 2012 19:23 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ HL~arc-en-ciel
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Old 26 àÁÉÒ¹ 2012, 22:43
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¤èÒ $\pi =3.14159 2653 \quad58\quad 9793 23846 26433 83279 50288 41971 69399 37510 58209 74944 59230...$

Íա˹Öè§ÊٵäèÒ $\pi =\frac{4}{1}-\frac{4}{3}+\frac{4}{5}-\frac{4}{7}+\frac{4}{9}-\frac{4}{11}+\frac{4}{13}-...$

26 àÁÉÒ¹ 2012 22:56 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 2 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ artty60
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Old 27 àÁÉÒ¹ 2012, 08:37
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à¡è§æ¡Ñ¹·Ø¡¤¹àŤÃѺ

¢éÍáá


The first 100 decimal digits of $ \pi \ $are 3.14159 26535 89793 23846 26433 83279 50288 41971 69399 37510 58209 74944 59230 78164 06286 20899 86280 34825 34211 70679...


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ref : http://en.wikipedia.org/wiki/Pi
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Old 27 àÁÉÒ¹ 2012, 09:02
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¢Í§á¶Á
¤ÇÒÁÊÑÁ¾Ñ¹¸ìÃÐËÇèÒ§ $ \ \sqrt{3} \ $ ¡Ñº $ \ \pi $

As a continued fraction, the square root of 3 can be written as :
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Here is pi series:

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For more on the next continued fraction below, see An Elegant Continued Fraction for Pi
by L J Large in American Mathematical Monthly vol 106, May 1999, pages 456-8.

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We research the connection between the value of sqrt (3) and the value of pi...
We use the equation :
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If we assume x=squart(3), we get:
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or:
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and:
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Pythagoras' Constant, the Square Root of 2, is related to the Archimedes` Constant pi, as shown below :
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or
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So, we get:

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ref : http://milan.milanovic.org/math/engl...t3/sqart3.html
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Old 27 àÁÉÒ¹ 2012, 09:58
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⨷ÂìÊÇÂáµè·ÓäÁèä´é
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  #11  
Old 28 àÁÉÒ¹ 2012, 17:09
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proof
$\sqrt{3}=1+\sqrt{3}-1$
$=1+ \frac{2}{\sqrt3+1}$
$=1+\frac{2}{2+\frac{2}{\sqrt3+1}}$
$=1+\frac{2}{2+\frac{2}{2+\frac{2}{\sqrt{3}+1}}}$
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28 àÁÉÒ¹ 2012 17:10 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 3 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ polsk133
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