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  #1  
Old 23 Á¡ÃÒ¤Á 2009, 13:50
lek_cha lek_cha äÁèÍÂÙèã¹Ãкº
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Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 11 ¡Ñ¹ÂÒ¹ 2007
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Default ͸ԺÒ Theorem ¹ÕéãËé·Õ¤ÃѺ

Let N be a contraction($\delta < 1$) ,if we assume that$||F_n-N||=\epsilon _n\rightarrow _{n\rightarrow \infty }0$,then the sequence ${S_n}$ given by

$S_{n+1}=F(x_0+S_n),\qquad S_0=0$

converges to the S, solution of $F(x_0+S)=S$

͸ԺÒÂãËé·Õ¤ÃѺ ¼Áá»ÃáÅéǧ§§èФÃѺ

¢Íº¤Ø³¤ÃѺ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #2  
Old 30 Á¡ÃÒ¤Á 2009, 10:03
nooonuii nooonuii äÁèÍÂÙèã¹Ãкº
¼Ùé¾Ô·Ñ¡Éì¡®·ÑèÇä»
 
Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 25 ¾ÄÉÀÒ¤Á 2001
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Default

ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ lek_cha View Post
Let N be a contraction($\delta < 1$) ,if we assume that$||F_n-N||=\epsilon _n\rightarrow _{n\rightarrow \infty }0$,then the sequence ${S_n}$ given by

$S_{n+1}=F(x_0+S_n),\qquad S_0=0$

converges to the S, solution of $F(x_0+S)=S$

͸ԺÒÂãËé·Õ¤ÃѺ ¼Áá»ÃáÅéǧ§§èФÃѺ

¢Íº¤Ø³¤ÃѺ
$F_n$ ¡Ñº $F$ ÊÑÁ¾Ñ¹¸ì¡Ñ¹Âѧ䧤ÃѺ

$F_n\to F$ ãªèËÃ×ÍäÁè
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