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ÊÁѤÃÊÁÒªÔ¡ ¤ÙèÁ×Í¡ÒÃãªé ÃÒª×èÍÊÁÒªÔ¡ »¯Ô·Ô¹ ¢éͤÇÒÁÇѹ¹Õé

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  #1  
Old 01 ¡Ã¡®Ò¤Á 2015, 22:24
mark123 ^.^ mark123 ^.^ äÁèÍÂÙèã¹Ãкº
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Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 06 àÁÉÒ¹ 2013
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ã¹·Ò§¤³ÔµÈÒʵÃì ä´éÁÕ¡ÒùÔÂÒÁ¶Ö§Í¹Ø¾Ñ¹¸ìÇèÒ
$\lim_{h \to 0}\frac{f(x+h)-f(x)}{h} = f'(x)$
¤×ͼÁʧÊÑÂÇèÒàÃÒä´éÁÕ¡ÒùÔÂÒÁà¡ÕèÂǡѺ $f^\frac{1}{2}(x)$ ËÃ×Í $f^\frac{1}{3}(x)$ äËÁ
â´Â·Õè $f^\frac{1}{2}(x)$ ¤×Í͹ؾѹ¸ìÍѹ´Ñº·Õè 0.5 áÅéǶéÒà¡Ô´ÁըйÔÂÒÁâ´ÂÍÐäÃáÅйÓä»ãªéÍÂèÒ§äÃ
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  #2  
Old 01 ¡Ã¡®Ò¤Á 2015, 23:02
nooonuii nooonuii äÁèÍÂÙèã¹Ãкº
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áµè¡ç¾ÍÃÙéÁÒºéÒ§ÇèÒà¢ÒÈÖ¡ÉÒàÃ×èͧ¹Õé¡Ñ¹ÍÂèÒ§¨ÃÔ§¨Ñ§áÅÐÁÕ¡ÒûÃÐÂØ¡µìãªé´éÇÂ

àªè¹ã¹¹Õé http://www3.nd.edu/~msen/Teaching/UnderRes/FracCalc.pdf
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  #3  
Old 02 ¡Ã¡®Ò¤Á 2015, 20:40
mark123 ^.^ mark123 ^.^ äÁèÍÂÙèã¹Ãкº
ËÑ´à´Ô¹ÅÁ»ÃÒ³
 
Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 06 àÁÉÒ¹ 2013
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