็Help

[ballza]

$tan A - sec A = \sqrt[3]{37}$
จงหา${(tan A + sec A)}^3$

[RER]

$sec^2A-tan^2A=1------(1)$
$tanA-secA=\sqrt[3]{37}\rightarrow secA-tanA=-\sqrt[3]{37}-----(2)$
$(1)/(2); secA+tanA=-\frac{1}{\sqrt[3]{37}}$
$(secA+tanA)^3=-\frac{1}{37}$