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#2
21 ¡Ã¡®Ò¤Á 2010, 19:17
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¼ÅµèÒ§¡ÓÅѧ 3 ¹Ñè¹àͧ
$ A^3-B^3=(A-B)(A^2+AB+B^2) $ ´Ñ§¹Ñé¹ $ (a+b)^3-8b^3 = (a+b)^3-(2b)^3 $ ¹Ñè¹àͧ ·Óµè͹ФÃѺ
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#4
21 ¡Ã¡®Ò¤Á 2010, 20:34
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${(a+b)}^3-{(2b)}^3=[(a+b)-2b][{(a+b)}^2+(a+b)(2b)+{(2b)}^2]$ $=(a-b)(a^2+2ab+b^2+2ab+2b^2+4b^2)$ $=(a-b)(a^2+4ab+7b^2)$ ⨷Âì¤ØÁͧãªèÁÑé¤ÃѺà¹ÕèÂ
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#5
23 ¡Ã¡®Ò¤Á 2010, 21:18
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