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  #1  
Old 13 ÁԶعÒ¹ 2015, 19:25
kean kean äÁèÍÂÙèã¹Ãкº
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Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 11 ÁԶعÒ¹ 2012
¢éͤÇÒÁ: 15
kean is on a distinguished road
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¹éͧÁÒ¶ÒÁ¡ÒúéÒ¹¤ÃѺ¡ÓÅѧ¨ÐÊ͹¹éͧ áµè¾ÍÅͧ·ÓáÅéÇ ÅͧËÅÒÂÇÔ¸ÕÁѹä´é¤ÓµÍºäÁèà·èҡѹ
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13 ÁԶعÒ¹ 2015 19:25 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ kean
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #2  
Old 13 ÁԶعÒ¹ 2015, 21:12
RER RER äÁèÍÂÙèã¹Ãкº
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Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 04 àÁÉÒ¹ 2015
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RER is on a distinguished road
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äÁè¹èÒ¨ÐÁÕÍÐäùФÃѺ $\frac{6^{17}}{2^{17}\times3^{16}}=\frac{6^{17}}{2\times6^{16}}=\frac{6}{2}=3$
ËÃ×ÍÍÕ¡ÇÔ¸Õ $\frac{6^{17}}{2^{17}\times3^{16}}=\frac{3^{17}}{3^{16}}=3$
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #3  
Old 14 ÁԶعÒ¹ 2015, 18:01
Pitchayut Pitchayut äÁèÍÂÙèã¹Ãкº
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Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 20 Á¡ÃÒ¤Á 2015
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ÁÒà¾ÔèÁãËéÍÕ¡ÇÔ¸Õ $\dfrac{6^{17}}{2^{17} \times 3^{16}}=\dfrac{2^{17}\times 3^{17}}{2^{17}\times 3^{16}}=3$ äÁèÇèÒ¨ÐãªéÇÔ¸Õä˹Âѧ䧡çµéͧä´é $3$ ¤ÃѺ

14 ÁԶعÒ¹ 2015 18:02 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ Pitchayut
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
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