Mathcenter Forum  

Go Back   Mathcenter Forum > ¤³ÔµÈÒʵÃìÁѸÂÁÈÖ¡ÉÒ > »Ñ­ËÒ¤³ÔµÈÒʵÃì Á.»ÅÒÂ
ÊÁѤÃÊÁÒªÔ¡ ¤ÙèÁ×Í¡ÒÃãªé ÃÒª×èÍÊÁÒªÔ¡ »¯Ô·Ô¹ ¢éͤÇÒÁÇѹ¹Õé

µÑé§ËÑÇ¢éÍãËÁè Reply
 
à¤Ã×èͧÁ×ͧ͢ËÑÇ¢éÍ ¤é¹ËÒã¹ËÑÇ¢é͹Õé
  #1  
Old 25 ¸Ñ¹ÇÒ¤Á 2013, 23:36
Kenway Kenway äÁèÍÂÙèã¹Ãкº
ÊÁÒªÔ¡ãËÁè
 
Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 25 ¸Ñ¹ÇÒ¤Á 2013
¢éͤÇÒÁ: 4
Kenway is on a distinguished road
Default ¢Íá¹Ç¤Ô´àÃ×èͧµÃÕ⡳ÁÔµÔ¤ÃѺ

¶éÒà»ç¹áººÅÐàÍÕ´áÅéÇ¡çÁÕ¢Ñ鹵͹ä´é¡çÂÔ觴չФÃѺ

1) ¼Å¤Ù³¢Í§¤ÓµÍº¢Í§ÊÁ¡Òà tan^-1(3x^2+1) = 2tan^-1 1/2 à·èҡѺà·èÒã´

2) ¼ÅºÇ¡¢Í§¤ÓµÍºÊÁ¡Òà sin4x° + sin2x° = cos x° ÊÓËÃѺªèǧ x 㹪èǧ [0,360) à·èҡѺà·èÒã´

3)



¢Íº¾ÃФس¹Ð¤ÃѺ

25 ¸Ñ¹ÇÒ¤Á 2013 23:38 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ Kenway
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #2  
Old 26 ¸Ñ¹ÇÒ¤Á 2013, 14:45
Kenway Kenway äÁèÍÂÙèã¹Ãкº
ÊÁÒªÔ¡ãËÁè
 
Çѹ·ÕèÊÁѤÃÊÁÒªÔ¡: 25 ¸Ñ¹ÇÒ¤Á 2013
¢éͤÇÒÁ: 4
Kenway is on a distinguished road
Default

¢Íº¤Ø³¤ÃѺ
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
µÑé§ËÑÇ¢éÍãËÁè Reply



¡®¡ÒÃÊ觢éͤÇÒÁ
¤Ø³ äÁèÊÒÁÒö µÑé§ËÑÇ¢éÍãËÁèä´é
¤Ø³ äÁèÊÒÁÒö µÍºËÑÇ¢éÍä´é
¤Ø³ äÁèÊÒÁÒö Ṻä¿ÅìáÅÐàÍ¡ÊÒÃä´é
¤Ø³ äÁèÊÒÁÒö á¡é䢢éͤÇÒÁ¢Í§¤Ø³àͧä´é

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
·Ò§ÅÑ´ÊÙèËéͧ


àÇÅÒ·ÕèáÊ´§·Ñé§ËÁ´ à»ç¹àÇÅÒ·Õè»ÃÐà·Èä·Â (GMT +7) ¢³Ð¹Õéà»ç¹àÇÅÒ 11:00


Powered by vBulletin® Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.
Modified by Jetsada Karnpracha