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  #1  
Old 22 ¾ÄÉÀÒ¤Á 2019, 15:46
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$a_n = \frac{1+2+4+8+...+2^{n-1}}{3(1-2+4-8+...+(-2)^{n-1})}$

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  #2  
Old 10 ÁԶعÒ¹ 2019, 13:56
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  #3  
Old 10 ÁԶعÒ¹ 2019, 17:30
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Amankris Amankris äÁèÍÂÙèã¹Ãкº
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