|
ÊÁѤÃÊÁÒªÔ¡ | ¤ÙèÁ×Í¡ÒÃãªé | ÃÒª×èÍÊÁÒªÔ¡ | »¯Ô·Ô¹ | ¢éͤÇÒÁÇѹ¹Õé | ¤é¹ËÒ |
|
à¤Ã×èͧÁ×ͧ͢ËÑÇ¢éÍ | ¤é¹ËÒã¹ËÑÇ¢é͹Õé |
#1
|
|||
|
|||
ªèÇÂáÊ´§ÇÔ¸Õ·ÓãËé¼Á´Ù˹è͹ФѺ
|
#2
|
||||
|
||||
31.
$z_1=(\cos\frac{\pi}{16}+i\sin\frac{\pi}{16})^4=\cos\frac{\pi}{4}+i\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}i$ $z_2=2+i-\frac{\sqrt{2}}{\bar z_1}=2+i-\frac{\sqrt{2}}{\frac{1}{\sqrt{2}}-\frac{1}{\sqrt{2}}i}$ $=2+i-\frac{2}{1-i}=2+i-(1+i)=1$ $(f\circ g)(x)=\sqrt{3g(x)+1}=x^2+1\Rightarrow g(x)=\frac{1}{3}(x^2)(x^2+2)\Rightarrow g'(1)=\frac{4}{3}(1^3+1)=\frac{8}{3}$ $f'(x)=\frac{1}{2}(3x+1)^{-\frac{1}{2}}(3x+1)'\Rightarrow f'(1)=\frac{3}{2}(4^{-\frac{1}{2}})=\frac{3}{4}$ $f'(1)+g'(1)=\frac{8}{3}+\frac{3}{4}=\frac{41}{12}$
__________________
"¨§ÃÑ¡µÑÇàͧ´éÇ¡ÒêèÇÂàËÅ×ͼÙéÍ×è¹ áÅÐÃÑ¡¼ÙéÍ×è¹´éÇ¡ÒþѲ¹ÒµÑÇàͧ" << i'm lovin' it>> |
|
|