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#1
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⨷Âìá¤Å2 àÃ×èͧÃйҺ ªèÇÂ˹èͤÃѺ
¨§ËÒÊÁ¡ÒâͧÃйҺ·Õè¼èÒ¹¨Ø´ (1,2,3),(2,0,1) áÅеÑ駩ҡ¡ÑºÃйҺ x+y-z=3
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#2
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ÊÃéÒ§ÊÁ¡ÒÃÃйҺ µéͧÃÙé¨Ø´¼èÒ¹ 1 ¨Ø´ áÅÐ normal vector
¨Ø´¼èÒ¹ 2 ¨Ø´·ÕèãËéÁÒ ÊÃéÒ§àÇ¡àµÍÃ캹ÃйҺä´é $ \vec{v}= (2-1,0-2,1-3) =(1,-2,-2)$ à¹×èͧ¨Ò¡ÃйҺ⨷ÂìµÑ駩ҡ¡ÑºÃйҺ x+y-z=3 «Öè§ÁÕ normal vector $ \vec{n}=(1,1,-1)$ ´Ñ§¹Ñé¹ normal vector ¢Í§ÃйҺ·Õèµéͧ¡Òà ËÒä´é¨Ò¡ cross product ¢Í§ $\vec{v} $ áÅÐ $\vec{n}$ (ÅͧàÍÒ 2 ÃйҺÁҵѴà»ç¹¡Ò¡ºÒ·ÁØÁ©Ò¡ áÅéǨРget ¤ÃѺ) ÊÁÁµÔ¼ÅÅѾ¸ì¨Ò¡¡Òà cross ¤×Í $ ( n_x,n_y,n_z)$ ¶éÒàÃÒàÅ×Í¡¨Ø´¼èÒ¹ 1 ¨Ø´à»ç¹ (1,2,3) ¡ç¨Ðä´éÊÁ¡ÒÃÃйҺ ¤×Í $ n_x(x-1)+n_y(y-2)+n_z(z-3)=0$
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#3
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ÍéÒ§ÍÔ§:
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