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ÊÁѤÃÊÁÒªÔ¡ ¤ÙèÁ×Í¡ÒÃãªé ÃÒª×èÍÊÁÒªÔ¡ »¯Ô·Ô¹ ¢éͤÇÒÁÇѹ¹Õé

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  #1  
Old 10 Á¡ÃÒ¤Á 2015, 12:02
luffy2539 luffy2539 äÁèÍÂÙèã¹Ãкº
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¡Ó˹´ãËé an à»ç¹ÅӴѺàâҤ³Ôµ â´Â·Õè a1=sinx , a2=cosx, a3=tanx àÁ×èÍ x à»ç¹¨Ó¹Ç¹¨ÃÔ§
¤èÒ n ã¹¢éÍã´µèÍ仹Õé·Õè·ÓãËé an= 1+cosx
¡.4 ¢.5 ¤.6 §.7 ¨.8


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  #2  
Old 10 Á¡ÃÒ¤Á 2015, 16:50
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¡ÔµµÔ ¡ÔµµÔ äÁèÍÂÙèã¹Ãкº
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$a_1a_3=a_2^2$
$\frac{\sin^2x}{\cos x} =\cos^2 x$
$\sin^2x-\cos^3x=0$

$\cos^3x+\cos^2x-1=0 $
仵èÍäÁèä´éáÅéÇ
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  #3  
Old 10 Á¡ÃÒ¤Á 2015, 16:57
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FranceZii Siriseth FranceZii Siriseth äÁèÍÂÙèã¹Ãкº
ºÑ³±Ôµ¿éÒ
 
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¼ÁµÔ´àËÁ×͹¤Ø³¡ÔµµÔàŤÃѺ
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  #4  
Old 10 Á¡ÃÒ¤Á 2015, 18:49
Aquila Aquila äÁèÍÂÙèã¹Ãкº
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仵èÍä´éÊÔ¤ÃѺ ¨Ñ´´Õæ Áѹ¨Ðä´é $a_{n}=\frac{1}{\cos^2 x}$

àÊÃç¨áÅéÇãªé $\cos ^3x=\sin ^2x$

àÍÒä»äÅè¡Ñº $a_{n}=a_{1}r^{n-1}$

(àÅ×Í¡ $r=\frac{\cos x}{\sin x}$) á¡éÊÁ¡ÒÃä´é $n=8$
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #5  
Old 11 Á¡ÃÒ¤Á 2015, 11:18
luffy2539 luffy2539 äÁèÍÂÙèã¹Ãкº
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àÍèÍÍ §§ÍèÒ¤ÃѺº ú¡Ç¹¢ÍÅÐàÍÕ´˹èÍÂä´éÁÑé¤ÃѺº
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
  #6  
Old 11 Á¡ÃÒ¤Á 2015, 11:29
Aquila Aquila äÁèÍÂÙèã¹Ãкº
ºÑ³±Ôµ¿éÒ
 
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¨Ñ´ÃÙ» $\cos ^3x+\cos ^2x-1=0$ â§à¢éÒËÒ $a_{n}=1+\cos x$

áÅéÇ¡çàÍÒ $\cos ^3x=\sin ^2x$ ä»ËÒ $n$ ¨Ò¡ $a_{n}=a_{1}r^{n-1}$
µÍº¾ÃéÍÁÍéÒ§ÍÔ§¢éͤÇÒÁ¹Õé
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