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  #1  
Old 24 ¾ÄÉÀÒ¤Á 2010, 21:45
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$\frac{9}{10} +\frac{10}{11} +\frac{11}{12} +...+\frac{39}{40}=? $
$1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-... =? $
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  #2  
Old 24 ¾ÄÉÀÒ¤Á 2010, 22:01
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gnopy gnopy äÁèÍÂÙèã¹Ãкº
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¢é͹Õé¼Á fail «ÐáÅéÇ

07 ÁԶعÒ¹ 2010 08:57 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ gnopy
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  #3  
Old 24 ¾ÄÉÀÒ¤Á 2010, 22:16
nooonuii nooonuii äÁèÍÂÙèã¹Ãкº
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ÍéÒ§ÍÔ§:
¢éͤÇÒÁà´ÔÁà¢Õ¹â´Â¤Ø³ Beta View Post
$1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}-\cdots$
ªèÇÂáÊ´§ÇÔ¸Õ·ÓãËé´Ù˹èͤÃѺäÁè·ÃÒºÇèÒà»ç¹Í¹Ø¡ÃÁÎÒÃìÁ͹ԡÃÖà»ÅèÒ
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$1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+\cdots=\ln{2}$

ÁÒ¨Ò¡¡ÒáÃШÒÂ͹ءÃÁà·àÅÍÃì

$\ln{(1+x)}=x-\dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\cdots$
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  #4  
Old 06 ÁԶعÒ¹ 2010, 22:07
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