#1
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\[
a_n = [\frac{{n^2 + 8n + 10}}{{n + 9}}] \] ¨§ËҼźǡ30¾¨¹ìáá
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#2
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¨Ðä´é $a_n=(n-1)+\frac{19}{n+9}$
´Ñ§¹Ñ鹼źǡ30¾¨¹ìáá¤×Í $(1+2+3+...+29)+19(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}+...+\frac{1}{39})$ ä´é¤èÒ»ÃÐÁÒ³ 462.0669 |
#3
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ÁÒäÃÅФÃѺ¢Í·ÕèÁÒ´éǤÃѺ
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#4
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$\displaystyle\frac{n^{2}+8n+10}{n+9} = \displaystyle\frac{n^{2}+8n-9+19}{n+9}= \displaystyle\frac{(n+9)(n-1)+19}{n+9} $
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