#16
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¤ÃѺà´ÕëÂÇÅͧ·Ó´Ù ä´é 1/2 ãªèÁÑé¤ÃѺ¶éÒ -ÃÙ·3/2 Áѹ¨Ðà¡Ô¹ÁØÁÀÒÂã¹ 3 àËÅÕèÂÁ
¢éÍ 2 ªèÇÂ˹èͤÃѺ à¢éÒã¨â¨·Âìáµè·ÓäÁèä´éáÅéÇ¡çäÁèÃÙé¨ÐàÃÔèÁÂÑ§ä§ T^T 22 àÁÉÒ¹ 2011 23:06 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ nongtum à˵ؼÅ: double post+á¡éàÅ硹éÍÂâ»Ã´ãªé»ØèÁá¡éä¢ |
#17
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ÍéÒ§ÍÔ§:
´Ñ§¹Ñ鹤èÒ¹éÍÂÊØ´ ¤×ÍàÁ×èÍ $cos 3x=-1$ $\ \ \ \ \ -\frac{3\pi}{2}<3x<\frac{3\pi}{2}$ $3x=-\pi,\pi$ $x=....$
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¤³ÔµÈÒʵÃì ¤×Í ÀÒÉÒÊÒ¡Å ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁÊǧÒÁ ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁ¨ÃÔ§ µÔ´µÒÁªÁ¤ÅÔ»ÇÕ´ÕâÍä´é·Õèhttp://www.youtube.com/user/poperKM 22 àÁÉÒ¹ 2011 22:45 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 2 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ poper |
#18
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$ -1 < cos3x< 1 $ ÁÒÂѧä§ÍèФÃѺ
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#19
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¨Ò¡ªèǧ¢Í§ $-\frac{\pi}{2}<x<\frac{\pi}{2}$ ¨Ðä´éÇèÒ $-\frac{3\pi}{2}<3x<\frac{3\pi}{2}$
㹪èǧ§¹Õé $-1\leqslant cos3x\leqslant 1$ ¤ÃѺ(ÅͧÇҴǧ¡ÅÁ˹Öè§Ë¹èÇ´٤ÃѺ) ÍéÒ§ÍÔ§:
àÃÒä´é $a=\frac{1}{2},-\frac{\sqrt{3}}{2}$ ´Ñ§¹Ñé¹ $cos\theta=\frac{1}{2},-\frac{\sqrt{3}}{2}$ áÅéÇ¡çËÒ $\theta$ àÊÃç¨áÅéÇ¡çµÍºã¹ÃÙ»·ÑèÇ令ÃѺ
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¤³ÔµÈÒʵÃì ¤×Í ÀÒÉÒÊÒ¡Å ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁÊǧÒÁ ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁ¨ÃÔ§ µÔ´µÒÁªÁ¤ÅÔ»ÇÕ´ÕâÍä´é·Õèhttp://www.youtube.com/user/poperKM 22 àÁÉÒ¹ 2011 23:06 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ nongtum à˵ؼÅ: double post |
#20
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¾Õè¤ÃѺ¤×ÍàÍÒ 3 à¢éÒ令ٳãªèÁФÃѺ Áѹ¡ç¨Ðä´é -270<3x<270 ËÃͤÃѺËÃ×ÍÂѧ䧧§ - -* ¼ÁÁÐÃÙéÍÐ
¼Áà»ç¹à´ç¡·Õèà¢éÒã¨ÍÐäÃÂÒ¡¨Ô§æ¤ÃѺ - -* 22 àÁÉÒ¹ 2011 23:22 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ echimaru |
#21
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ãªèáÅéǤÃѺ
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¤³ÔµÈÒʵÃì ¤×Í ÀÒÉÒÊÒ¡Å ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁÊǧÒÁ ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁ¨ÃÔ§ µÔ´µÒÁªÁ¤ÅÔ»ÇÕ´ÕâÍä´é·Õèhttp://www.youtube.com/user/poperKM |
#22
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µéͧÁͧãËéÍÍ¡¡è͹ÇèÒ »ÑËÒÁѹÍÂÙè·Õèä˹¤ÃѺ
à·èÒ·Õè¼ÁÁͧ¨Ò¡¡ÃзÙé·Õè¤Ø³ echimaru â¾ÊµìäÇé 2 - 3 ¡ÃзÙé·Õè¼èÒ¹ÁÒ »ÑËÒÁѹÍÂÙè·Õè·Ñ¡ÉÐ ¾×é¹°Ò¹ Á.µé¹ ÂѧäÁèà¾Õ§¾Í¤ÃѺ µÍ¹¹ÕéâçàÃÕ¹à»Ô´áÅéÇàËÃͤÃѺ ¶Ö§µéͧ·Ó¡ÒúéÒ¹Êè§ÍÒ¨ÒÃÂì àË繺͡ÇèÒ ÍÂÙè Á.1 ¡ÓÅѧ¨Ð¢Öé¹ Á.2 ¤ÃÙÊ͹µÃÕ⡳áÅéÇËÃ×ͤÃѺ à¹×éÍËÒ Á.µé¹ ¤ÃÙÊ͹ãËéËÁ´áÅéÇËÃ×ͤÃѺ ¶éÒÂѧäÁèä´éÈÖ¡ÉÒà¹×éÍËÒ Á.µé¹ ·Ñé§ËÁ´ ¼Áá¹Ð¹ÓãËéä»ÈÖ¡ÉÒ¡è͹´Õ¡ÇèҹФÃѺ »ÑËÒºÒ§ÍÂèÒ§¨Ðä´éÁͧÍÍ¡ä´é´éǵÑÇàÃÒàͧ ÊèǹàÃ×èͧµÃÕ⡳ ¡ç¤ÇÃä»ÈÖ¡ÉÒ·Ó¤ÇÒÁà¢éÒã¨ÃÒÂÅÐàÍÕ´à¡ÕèÂǡѺ¡ÒÃËÒ¤èҿѧ¡çªÑ¹µÃÕ⡳ÁԵԨҡǧ¡ÅÁ˹Öè§Ë¹èÇÂãËé´ÕàÊÕ¡è͹ ¶éÒ¾×é¹°Ò¹àÃÒäÁè´Õ ¡ÒÃá¡é»ÑËÒÁѹ¡ç¨ÐµÔ´ æ ¢Ñ´ æ ÍÂèÒ§·Õèà»ç¹ÍÂÙè¹ÕèËÅФÃѺ ».Å. ¤ÃÙ·ÕèÊ͹¹èÒ¨ÐÃÙé»ÑËҢͧ¤Ø³áÅÐà¾×è͹㹪Ñé¹àÃÕ¹¹Ð¤ÃѺ 23 àÁÉÒ¹ 2011 16:18 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ lek2554 |
#23
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¢Íº¤Ø³¾Õè lek ÁÒ¡¤ÃѺ àÃ×èͧ¹Õé¼Á¡çäÁè¤èÍÂâË´à·èÒäËÃè µÍ¹¹ÕéâçàÃÕ¹ÂѧäÁèà»Ô´¤ÃѺ ¡çàÅÂËÑ´·Ó⨷Âì¡Ñº¤ÃÙ ¤×ÍàÃÕ¹仡è͹¹èФÃѺ
Êèǹ¾×é¹°Ò¹¼ÁäÁè´Õ¨ÃÔ§æ¼Á¨Ð¾ÂÒÂÒÁÍèÒ¹áÅзӤÇÒÁà¢éÒ㨠¢Íº¤Ø³¾Õè lek ÁÒ¡¤ÃѺ |
#24
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¢é͵èÍ令ÃѺ
$tan\theta=cos\theta$ ,$sin\theta$ =? 26 àÁÉÒ¹ 2011 20:07 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 3 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ echimaru |
#25
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$\frac{sin\theta}{cos\theta}=cos\theta$
$sin\theta = cos^2\theta$ ¨Ò¡ $sin^\theta+cos^2\theta = 1$ $cos^2\theta = 1-sin^2\theta$ á·¹Å§ä» $sin\theta = 1-sin^2\theta$ $sin^2\theta +sin\theta -1 = 0$ ãËé $sin\theta=x$ $x^2+x-1 = 0$ ¨ºáÅéǹФÃѺ ãªéÊÙµÃÊÁ¡ÒáÓÅѧÊͧ¡ç¨º |
#26
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$tan\theta= \frac{sin \theta }{cos \theta }$
$cos \theta = \frac{sin \theta }{cos \theta }$ $ \therefore sin \theta = cos^2 \theta $ ¨Ò¡ $ sin^2 \theta + cos^2 \theta = 1$ $ sin^2 \theta + sin \theta -1 = 0$ ä´é $sin \theta = \frac{-1 + \sqrt{5} }{2}$ |
#27
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¡Ó˹´ãËé $A,B,C \in (0,\frac{\pi }{2} )$ áÅÐ $cos A = tan B ,cos B = tan C,cos C =tan A$
¨§áÊ´§ÇèÒ $sin A=sin B=sin C$ áÅШ§ËÒ¤èҢͧ sin A ªèÇ·դÃѺ 27 àÁÉÒ¹ 2011 21:51 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ echimaru |
#28
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ÍéÒ§ÍÔ§:
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#29
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Å´µÑÇá»ÃãËéàËÅ×Í3 µÑÇá»Ã
§§Íѹ¹ÕèÍèФÃѺ ¢Íâ·É¹Ð¤ÃѺ¾Ç¡¾Õè㹺ÍÃì´¹Õè¡ÇèÒ¨Ðà¡è§·Ó⨷Âì¡Ñ¹àÂÍÐÁÑé¤ÃѺ ¨ÐàÍÒà»ç¹µÑÇÍÂèÒ§ÍèФÃѺ 30 àÁÉÒ¹ 2011 02:24 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ nongtum à˵ؼÅ: double post+á¡éàÅ硹éÍÂâ»Ã´ãªé»ØèÁá¡éä¢ |
#30
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#29
¶éÒ´ÙµÒÁ⨷ÂìÁѹà»ç¹ 3 ÊÁ¡Òà 6 µÑÇá»ÃäÁèãªèËÃ×Í ¶éÒÁͧäÁèÍÍ¡ ¼Áä´éãËéá¹Ç·Ò§·Õè¨Ð仵èÍã¹ hint 2 |
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