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#1
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͹ءÃÁ͹ѹµì¤ÃѺ
¨§ËÒ¤èҢͧ $$1-\frac{2}{4}+\frac{2\times5}{4\times8}-\frac{2\times5\times8}{4\times8\times12}+.....$$ ã¤ÃÁÕ¤Óàà¹Ð¹Ó ªèÇÂ˹èͤÃѺ
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»Õ¹Õé µéͧäÁè¾ÅÒ´ ÊÙéà¾×èÍ ÁÈÇ »·ØÁÇѹ 22 ¡ØÁÀҾѹ¸ì 2013 11:15 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ à·¾àÇÕ¹à¡Ô´ |
#2
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à¤Ã×èͧËÁÒ $\times$ ãªé¤ÓÊÑè§ \times ¤ÃѺ
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site:mathcenter.net ¤Ó¤é¹ |
#3
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ÍéÒ§ÍÔ§:
´Ñ§¹Ñé¹ $(1-x)^n = 1 - nx + \frac{n(n-1)}{2!}x^2 - \frac{n(n-1)(n-2)}{3!}x^3+...$
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The Lost Emic <<-- ˹ѧÊ×Íà©Å¢éÍÊͺÃдѺ»ÃжÁ¹Ò¹ÒªÒµÔ EMIC ¤ÃÑ駷Õè 1 - ¤ÃÑ駷Õè 8 ªØ´ÊØ´·éÒ ËŧÁÒ 07 ¡Ã¡®Ò¤Á 2012 23:42 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ gon |
#4
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¢Í¢ÂÒµèÍÍÕ¡¹Ô´¹Ð¤ÃѺ Âѧ¹Ö¡äÁèÍÍ¡àÅÂ
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WHAT MAN BELIEVES MAN CAN ACHIEVE |
#5
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µÒÁÊٵ÷Õè·èÒ¹ gon ãËéÁÒ
$$1-\frac{2}{4}+\frac{2\times5}{4\times8}-\frac{2\times5\times8}{4\times8\times12}+...=1-nx+\frac{n(n-1)}{2!}x^2-...$$ à·ÕºÊÑÁ»ÃÐÊÔ·¸Ôì $nx=\frac{2}{4}$--------(1) $\frac{n(n-1)}{2!}x^2=\frac{2\times5}{4\times8}$-------(2) á¡éËÒ¤èÒ $n$ áÅÐ $x$ áÅéÇá·¹¤èÒ ·ÕèËÒä´éã¹ $(1-x)^n$ ¤ÃѺ
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¤³ÔµÈÒʵÃì ¤×Í ÀÒÉÒÊÒ¡Å ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁÊǧÒÁ ¤³ÔµÈÒʵÃì ¤×Í ¤ÇÒÁ¨ÃÔ§ µÔ´µÒÁªÁ¤ÅÔ»ÇÕ´ÕâÍä´é·Õèhttp://www.youtube.com/user/poperKM 28 ¾ÄȨԡÒ¹ 2012 08:31 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ poper |
#6
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#5 ¾Õègon ¤ÃѺ
áÅÐàÁ×èͤԴµèͨÐä´é¤èÒ $n=\frac{-2}{3}$ , $x= \frac{-3}{4}$ á·¹¤èÒ¡é¨Ðä´é $\sqrt[3]{\frac{16}{49}}$ |
#7
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¢Íº¤Ø³¤ÃѺ¼Á ¹Ñè§ËÒ¤ÇÒÁÊÑÁ¾Ñ¹¸ìµÑ駹ҹ ËÒäÁèä´é ãªé Combi ¹Õèàͧ
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»Õ¹Õé µéͧäÁè¾ÅÒ´ ÊÙéà¾×èÍ ÁÈÇ »·ØÁÇѹ |
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